I would suggest level shifters , amplification causes unnecessary distortion unless you know what is coupled to it. Opamp is good , it is better you check the signal that drives it.
I would suggest level shifters , amplification causes unnecessary distortion unless you know what is coupled to it. Opamp is good , it is better you check the signal that drives it.
To convert from 3.3 V to 5 V a simple HCT gate (output CMOS, input TTL compatible) would do. BUT: assuming you measured the signal distortion on the IGBT gate: this is a significant capacitive load (with quite a number of parasitics) so you will always see distortion here. To drive an IGBT satisfactorily, you need a rather capable power stage (current drive levels in the single-digit amperes). AND - as it is - I hope your IGBT is accepting voltages beyond 5 V - as 5 V seems a bit low for an IGBT. Looking into the data sheet of the HCPL: 0.6 A peak current is still not much when driving an IGBT. You may want to search something in the 2 A peak current range. Or design an "afterburner" (e.g. an emitter follower with BJTs) that boosts the output of HCPL. Regards
To convert from 3.3 V to 5 V a simple HCT gate (output CMOS, input TTL compatible) would do. BUT: assuming you measured the signal distortion on the IGBT gate: this is a significant capacitive load (with quite a number of parasitics) so you will always see distortion here. To drive an IGBT satisfactorily, you need a rather capable power stage (current drive levels in the single-digit amperes). AND - as it is - I hope your IGBT is accepting voltages beyond 5 V - as 5 V seems a bit low for an IGBT. Looking into the data sheet of the HCPL: 0.6 A peak current is still not much when driving an IGBT. You may want to search something in the 2 A peak current range. Or design an "afterburner" (e.g. an emitter follower with BJTs) that boosts the output of HCPL. Regards
Simple FET based NOT gate will work just change Vcc on the top of the drain to 5V Make sure V_gs_on for your FET is <3.3 If you use the HCPL-3101 the diode just goes in series with the drain resistor (which should be sized for the load current of the diode inside the HCPLL-3101 which looks to be 14-20mA and then tie VCC to your 15-30V supply - same requirement on the gate to source turn on voltage though.
Simple FET based NOT gate will work just change Vcc on the top of the drain to 5V Make sure V_gs_on for your FET is <3.3 If you use the HCPL-3101 the diode just goes in series with the drain resistor (which should be sized for the load current of the diode inside the HCPLL-3101 which looks to be 14-20mA and then tie VCC to your 15-30V supply - same requirement on the gate to source turn on voltage though.
FPGA system used to generate the gate pulse to switch ON/OFF IGBT in system. Voltage of these pulse may be less than 3.3V .you use Driver IC (e.g. IR2109) corresponding to selected IGBT. driver IC will provide pulse having voltage up to 12V . Pulses from FPGA board are applied to Opto-oupler. Output of Opto-coupler is apply to Driver IC and output of Driver IC is connected to Gate terminal of IGBT
FPGA system used to generate the gate pulse to switch ON/OFF IGBT in system. Voltage of these pulse may be less than 3.3V .you use Driver IC (e.g. IR2109) corresponding to selected IGBT. driver IC will provide pulse having voltage up to 12V . Pulses from FPGA board are applied to Opto-oupler. Output of Opto-coupler is apply to Driver IC and output of Driver IC is connected to Gate terminal of IGBT
You can also use something like this - it gives you the ability to arbitrarily set logic levels on each side of the translator - slight modification on the above circuit I mentioned. While op amps can work - its total overkill. These kinds of transistor solutions are simple and very cost effective.
https://solarbotics.com/product/50550/?gclid=Cj0KEQjw5Z63BRCLqqLtpc6dk7gBEiQA0OuhsJDSq3uK0X6VUDuDQoBYMPC77tqAdgIJRDJhvtiWOlUaAv3R8P8HAQ
You can also use something like this - it gives you the ability to arbitrarily set logic levels on each side of the translator - slight modification on the above circuit I mentioned. While op amps can work - its total overkill. These kinds of transistor solutions are simple and very cost effective.
https://solarbotics.com/product/50550/?gclid=Cj0KEQjw5Z63BRCLqqLtpc6dk7gBEiQA0OuhsJDSq3uK0X6VUDuDQoBYMPC77tqAdgIJRDJhvtiWOlUaAv3R8P8HAQ
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Referring to the data sheet the HCPL3101 looks to need a minimum of a 15V supply.
Try a UC3705T MOSFET Power Driver which works from 5 → 40V. If you need isolation place a fast logic opto beforehand.
http://datasheet.octopart.com/HCPL-3101-000E-Avago-datasheet-8218370.pdf
http://www.ti.com/lit/ds/symlink/uc1705.pdf
Referring to the data sheet the HCPL3101 looks to need a minimum of a 15V supply.
Try a UC3705T MOSFET Power Driver which works from 5 → 40V. If you need isolation place a fast logic opto beforehand.
http://datasheet.octopart.com/HCPL-3101-000E-Avago-datasheet-8218370.pdf
http://www.ti.com/lit/ds/symlink/uc1705.pdf
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I would suggest level shifters , amplification causes unnecessary distortion unless you know what is coupled to it.
Opamp is good , it is better you check the signal that drives it.
I would suggest level shifters , amplification causes unnecessary distortion unless you know what is coupled to it.
Opamp is good , it is better you check the signal that drives it.
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VOTE
There are logic level converter chips which exactly functions as logic level conversion. Accurate solution without any headache...
There are logic level converter chips which exactly functions as logic level conversion. Accurate solution without any headache...
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2
2
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To convert from 3.3 V to 5 V a simple HCT gate (output CMOS, input TTL compatible) would do.
BUT: assuming you measured the signal distortion on the IGBT gate: this is a significant capacitive load (with quite a number of parasitics) so you will always see distortion here. To drive an IGBT satisfactorily, you need a rather capable power stage (current drive levels in the single-digit amperes). AND - as it is - I hope your IGBT is accepting voltages beyond 5 V - as 5 V seems a bit low for an IGBT.
Looking into the data sheet of the HCPL: 0.6 A peak current is still not much when driving an IGBT. You may want to search something in the 2 A peak current range. Or design an "afterburner" (e.g. an emitter follower with BJTs) that boosts the output of HCPL.
Regards
To convert from 3.3 V to 5 V a simple HCT gate (output CMOS, input TTL compatible) would do.
BUT: assuming you measured the signal distortion on the IGBT gate: this is a significant capacitive load (with quite a number of parasitics) so you will always see distortion here. To drive an IGBT satisfactorily, you need a rather capable power stage (current drive levels in the single-digit amperes). AND - as it is - I hope your IGBT is accepting voltages beyond 5 V - as 5 V seems a bit low for an IGBT.
Looking into the data sheet of the HCPL: 0.6 A peak current is still not much when driving an IGBT. You may want to search something in the 2 A peak current range. Or design an "afterburner" (e.g. an emitter follower with BJTs) that boosts the output of HCPL.
Regards
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https://pdfs.semanticscholar.org/fd50/10ba6aa439dd3e6ea8cf059f0461dd21c378.pdf?_ga=2.177946789.1263147309.1555559589-164360384.1555559589
https://pdfs.semanticscholar.org/fd50/10ba6aa439dd3e6ea8cf059f0461dd21c378.pdf?_ga=2.177946789.1263147309.1555559589-164360384.1555559589
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Simple FET based NOT gate will work just change Vcc on the top of the drain to 5V
Make sure V_gs_on for your FET is <3.3
If you use the HCPL-3101 the diode just goes in series with the drain resistor (which should be sized for the load current of the diode inside the HCPLL-3101 which looks to be 14-20mA and then tie VCC to your 15-30V supply - same requirement on the gate to source turn on voltage though.
Simple FET based NOT gate will work just change Vcc on the top of the drain to 5V
Make sure V_gs_on for your FET is <3.3
If you use the HCPL-3101 the diode just goes in series with the drain resistor (which should be sized for the load current of the diode inside the HCPLL-3101 which looks to be 14-20mA and then tie VCC to your 15-30V supply - same requirement on the gate to source turn on voltage though.
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https://www.sparkfun.com/products/12009
http://electronics.stackexchange.com/questions/81580/step-up-3-3v-to-5v-for-digital-i-o
https://www.sparkfun.com/products/12009
http://electronics.stackexchange.com/questions/81580/step-up-3-3v-to-5v-for-digital-i-o
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FPGA system used to generate the gate pulse to switch ON/OFF IGBT in system. Voltage of these pulse may be less than 3.3V .you use Driver IC (e.g. IR2109) corresponding to selected IGBT. driver IC will provide pulse having voltage up to 12V .
Pulses from FPGA board are applied to Opto-oupler. Output of Opto-coupler is apply to Driver IC and output of Driver IC is connected to Gate terminal of IGBT
FPGA system used to generate the gate pulse to switch ON/OFF IGBT in system. Voltage of these pulse may be less than 3.3V .you use Driver IC (e.g. IR2109) corresponding to selected IGBT. driver IC will provide pulse having voltage up to 12V .
Pulses from FPGA board are applied to Opto-oupler. Output of Opto-coupler is apply to Driver IC and output of Driver IC is connected to Gate terminal of IGBT
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