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Can propyne be prepared from calcium carbide and water? If so, how?
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Mani Bhullar
Can propyne be prepared from calcium carbide and water? If so, how?
Directly (e.g., one step), no. The reaction of calcium carbide (CaC2) and water (H2O) results in the formation of acetylene (HCCH).
2 H2O + CaC2 → HCCH + Ca(OH)2
Now, if you react the acetylene with one equivalent of n-butyl lithium (CH3CH2CH2CH2-Li) in THF and then add one equivalent of methyl iodide (CH3I) you will get propyne
Directly (e.g., one step), no. The reaction of calcium carbide (CaC2) and water (H2O) results in the formation of acetylene (HCCH).
2 H2O + CaC2 → HCCH + Ca(OH)2
Now, if you react the acetylene with one equivalent of n-butyl lithium (CH3CH2CH2CH2-Li) in THF and then add one equivalent of methyl iodide (CH3I) you will get propyne
Directly (e.g., one step), no. The reaction of calcium carbide (CaC2) and water (H2O) results in the formation of acetylene (HCCH).
2 H2O + CaC2 → HCCH + Ca(OH)2
Now, if you react the acetylene with one equivalent of n-butyl lithium (CH3CH2CH2CH2-Li) in THF and then add one equivalent of methyl iodide (CH3I) you will get propyne
HCCH + n-butyl lithium → HCC-Li + CH3CH2CH2CH3
HCC-Li + CH3-I → HCC-CH3 + LiI
Directly (e.g., one step), no. The reaction of calcium carbide (CaC2) and water (H2O) results in the formation of acetylene (HCCH).
2 H2O + CaC2 → HCCH + Ca(OH)2
Now, if you react the acetylene with one equivalent of n-butyl lithium (CH3CH2CH2CH2-Li) in THF and then add one equivalent of methyl iodide (CH3I) you will get propyne
HCCH + n-butyl lithium → HCC-Li + CH3CH2CH2CH3
HCC-Li + CH3-I → HCC-CH3 + LiI
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Hmm, the necessary atomic constituents are there, so yes. But, it wouldn’t be a simple process. Probably like 10–20 different processes.
Hmm, the necessary atomic constituents are there, so yes. But, it wouldn’t be a simple process. Probably like 10–20 different processes.
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