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Determining iron content by titration
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Determining iron content by titration
In order for you to carry out this reaction, you need potassium permanganate, which provides the ion $\ce{MnO4^-}$. You also need sulfuric acid, and quite a lot of this acid, because the equation requires $\ce{8 H^+}$. And well ! $8$ is much ! So the reaction will not work without acid. And you still need $5$ electrons, which are provided by $\ce{5 Fe^{2+}}$ ion. The $\ce{K+}$ brought by the potassium permanganate remains in the solution as spectator. They don't react.
In order for you to carry out this reaction, you need potassium permanganate, which provides the ion $\ce{MnO4^-}$. You also need sulfuric acid, and quite a lot of this acid, because the equation requires $\ce{8 H^+}$. And well ! $8$ is much ! So the reaction will not work without acid. And you still need $5$ electrons, which are provided by $\ce{5 Fe^{2+}}$ ion. The $\ce{K+}$ brought by the potassium permanganate remains in the solution as spectator. They don't react.
In the experiment sheet it does not mention anything about sulfuric acid. It only mentions 100ml ground water and 6.5x10-5 mol l-1 potassium permanganate. So I’m this case how much sulfuric acid is needed?More
@Lulu. $\pu{100 mL}$ ground water has a meaning. But $\pu{6.5E{-5} mol L^{-1}}$ permanganate has no meaning. One should give you an information like "XXX milliliters of potassium permanganate having a concentration of YYY mole per liter was used for titrating this amount of ground water"More
In order for you to carry out this reaction, you need potassium permanganate, which provides the ion $\ce{MnO4^-}$. You also need sulfuric acid, and quite a lot of this acid, because the equation requires $\ce{8 H^+}$. And well ! $8$ is much ! So the reaction will not work without acid. And you still need $5$ electrons, which are provided by $\ce{5 Fe^{2+}}$ ion. The $\ce{K+}$ brought by the potassium permanganate remains in the solution as spectator. They don't react.
In order for you to carry out this reaction, you need potassium permanganate, which provides the ion $\ce{MnO4^-}$. You also need sulfuric acid, and quite a lot of this acid, because the equation requires $\ce{8 H^+}$. And well ! $8$ is much ! So the reaction will not work without acid. And you still need $5$ electrons, which are provided by $\ce{5 Fe^{2+}}$ ion. The $\ce{K+}$ brought by the potassium permanganate remains in the solution as spectator. They don't react.
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