19
Molar mass of H2SO4=98gmol
Molarity = massmolar mass × 1vol.of solvent in dm3
0.5 = m98 × 11
m=49g
Thus add 49 g H2So4 in measuring flask of add small quantity of solvent and shake well then fill the flask till 1 litre.
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VOTE
Start with basic chemistry -
C1V1 = C2V2
where:
C1 = Concentration of undiluted acid in moles
C2 = Concentration of the diluted acid in moles
V2 = Volume of diluted acid you want
Solve for V1 (how much concentrated acid of a given molarity you need) via
V1 = (C2V2)/C1
So - if you are starting with “98% w/w” (high grade) sulphuric acid and you want to make 1 litre of 0.5M Sulphuric Acid.
98% w/w Sulphuric acid = 18.4M Sulphuric acid
V1 = [(0.5 * 1000)/18.4] mls
= 27.2 ml (approx) of 98% Sulphuric acid
Dilute to 1000ml with distilled water to give 1L of 0.5M acid
2026-06-19
Molar mass of H2SO4=98gmol
Molarity = massmolar mass × 1vol.of solvent in dm3
0.5 = m98 × 11
m=49g
Thus add 49 g H2So4 in measuring flask of add small quantity of solvent and shake well then fill the flask till 1 litre.
Molar mass of H2SO4=98gmol
Molarity = massmolar mass × 1vol.of solvent in dm3
0.5 = m98 × 11
m=49g
Thus add 49 g H2So4 in measuring flask of add small quantity of solvent and shake well then fill the flask till 1 litre.
More
VOTE
Start with basic chemistry -
C1V1 = C2V2
where:
C1 = Concentration of undiluted acid in moles
C2 = Concentration of the diluted acid in moles
V2 = Volume of diluted acid you want
Solve for V1 (how much concentrated acid of a given molarity you need) via
V1 = (C2V2)/C1
So - if you are starting with “98% w/w” (high grade) sulphuric acid and you want to make 1 litre of 0.5M Sulphuric Acid.
98% w/w Sulphuric acid = 18.4M Sulphuric acid
V1 = [(0.5 * 1000)/18.4] mls
= 27.2 ml (approx) of 98% Sulphuric acid
Dilute to 1000ml with distilled water to give 1L of 0.5M acid
Start with basic chemistry -
C1V1 = C2V2
where:
C1 = Concentration of undiluted acid in moles
C2 = Concentration of the diluted acid in moles
V2 = Volume of diluted acid you want
Solve for V1 (how much concentrated acid of a given molarity you need) via
V1 = (C2V2)/C1
So - if you are starting with “98% w/w” (high grade) sulphuric acid and you want to make 1 litre of 0.5M Sulphuric Acid.
98% w/w Sulphuric acid = 18.4M Sulphuric acid
V1 = [(0.5 * 1000)/18.4] mls
= 27.2 ml (approx) of 98% Sulphuric acid
Dilute to 1000ml with distilled water to give 1L of 0.5M acid
More
VOTE