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We know,N= W/MV
or,W= NMV
= 1×40×0.1
= 4g
i.e.4g NaOH is needed for the preparation of 1N NaOH in 100 ml solution
More
VOTE
We know that N=M for NaOH because acidity of NaOH is one.
Molar mass of NaoH = 40
Mole = weight / molecular mass = 40 /40 = 1mole
Ml in litere = 100/1000=0.1 L
So molarity(M) = 1 mole/1 litre = 40 / 1 litre its 1 molerity = 1N normality
If you wanna make it in 100 ml than 4 gm in 0.1 litere
Ans = 4 gm (0.1 mole in 0.1 litre = 1M= 1N)
2026-07-07
We know,N= W/MV
or,W= NMV
= 1×40×0.1
= 4g
i.e.4g NaOH is needed for the preparation of 1N NaOH in 100 ml solution
We know,N= W/MV
or,W= NMV
= 1×40×0.1
= 4g
i.e.4g NaOH is needed for the preparation of 1N NaOH in 100 ml solution
More
VOTE
We know that N=M for NaOH because acidity of NaOH is one.
Molar mass of NaoH = 40
Mole = weight / molecular mass = 40 /40 = 1mole
Ml in litere = 100/1000=0.1 L
So molarity(M) = 1 mole/1 litre = 40 / 1 litre its 1 molerity = 1N normality
If you wanna make it in 100 ml than 4 gm in 0.1 litere
Ans = 4 gm (0.1 mole in 0.1 litre = 1M= 1N)
We know that N=M for NaOH because acidity of NaOH is one.
Molar mass of NaoH = 40
Mole = weight / molecular mass = 40 /40 = 1mole
Ml in litere = 100/1000=0.1 L
So molarity(M) = 1 mole/1 litre = 40 / 1 litre its 1 molerity = 1N normality
If you wanna make it in 100 ml than 4 gm in 0.1 litere
Ans = 4 gm (0.1 mole in 0.1 litre = 1M= 1N)
More
VOTE