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How do I solve this problem on mass balance from blast furnace iron making?
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Latin Game
How do I solve this problem on mass balance from blast furnace iron making?
"The Mn in iron ore should be equal to Mn in slag." vs
"the solution in my book reads MnO from ore equals Mn in hot metal plus MnO in slag."
It seems that the calculation desired involves breaking down the MnO in ore to Mn + O, and putting some of the Mn into the metal; the rest of the Mn goes into slag, as MnO. The hot metal would contain only metallic Mn, not MnO. It shouldn't be a huge adjustment in the answers.
"The Mn in iron ore should be equal to Mn in slag." vs"the solution in my book reads MnO from ore equals Mn in hot metal plus MnO in slag."
It seems that the calculation desired involves breaking down the MnO in ore to Mn + O, and putting some of the Mn into the metal; the rest of the Mn goes into slag, as MnO. The hot metal would contain only metallic Mn, not MnO. It shouldn't be a huge adjustment in the answers.
Please tell me something..while balacing MnO why am I not taking the $O_2$ that needs to be liberated into consideration.If MnO in iron ore give Mn in Hot Metal+MnO in slag.The oxygen should go somewhere.But my solution neglects that completely.More
Iron ore has Fe2O3. The O goes off with C as CO/CO2. The MnO in iron ore has to lose its O just like the Fe2O3 does. Consider Al2O3 and SiO2 to keep their oxygen; likewise H2O just evaporates. The coke has CaO and SiO2: they keep their oxygen. The overall process takes oxygen-containing metallic compounds and coke and limestone turns them into hot metal and slag and CO/CO2 + H2O. Consider the O in MnO (some of it) to go off as CO/CO2, just like the O in Fe2O3.More
"The Mn in iron ore should be equal to Mn in slag." vs "the solution in my book reads MnO from ore equals Mn in hot metal plus MnO in slag."
It seems that the calculation desired involves breaking down the MnO in ore to Mn + O, and putting some of the Mn into the metal; the rest of the Mn goes into slag, as MnO. The hot metal would contain only metallic Mn, not MnO. It shouldn't be a huge adjustment in the answers.
"The Mn in iron ore should be equal to Mn in slag." vs"the solution in my book reads MnO from ore equals Mn in hot metal plus MnO in slag."
It seems that the calculation desired involves breaking down the MnO in ore to Mn + O, and putting some of the Mn into the metal; the rest of the Mn goes into slag, as MnO. The hot metal would contain only metallic Mn, not MnO. It shouldn't be a huge adjustment in the answers.
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