If you are referring to a question dealing with the dissociation of an acid, the answer depends on the identity of the acid.
Strong acid dissociate completely in aqueous solution. Hydrochloric acid is an example, The value of [H^+] in 0.10 M HCl is 0.10 M.
Weak acids do not dissociate completely. Finding the value of [H^+] requires knowing the value of Ka for the acid and the initial concentration of the solution.
If you are referring to a question dealing with the dissociation of an acid, the answer depends on the identity of the acid.
Strong acid dissociate completely in aqueous solution. Hydrochloric acid is an example, The value of [H^+] in 0.10 M HCl is 0.10 M.
Weak acids do not dissociate completely. Finding the value of [H^+] requires knowing the value of Ka for the acid and the initial concentration of the solution.
As a quora user who asks how many inches in a foot, you’re in WAY.over your head with this question!
As a quora user who asks how many inches in a foot, you’re in WAY.over your head with this question!
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If you are referring to a question dealing with the dissociation of an acid, the answer depends on the identity of the acid.
Strong acid dissociate completely in aqueous solution. Hydrochloric acid is an example, The value of [H^+] in 0.10 M HCl is 0.10 M.
Weak acids do not dissociate completely. Finding the value of [H^+] requires knowing the value of Ka for the acid and the initial concentration of the solution.
Consider 0.10 M acetic acid, CH3COOH.
Ka = 1.8E-5 = [H^+][CH3COO^-]/[CH3COOH]
1.8E-5 = (y)(y)/0.10-y)
This is solved quickly by assuming y<<0.10.
That gives y = 0.0013 (Assumption valid!)
“E” represents “x10^”
If you are referring to a question dealing with the dissociation of an acid, the answer depends on the identity of the acid.
Strong acid dissociate completely in aqueous solution. Hydrochloric acid is an example, The value of [H^+] in 0.10 M HCl is 0.10 M.
Weak acids do not dissociate completely. Finding the value of [H^+] requires knowing the value of Ka for the acid and the initial concentration of the solution.
Consider 0.10 M acetic acid, CH3COOH.
Ka = 1.8E-5 = [H^+][CH3COO^-]/[CH3COOH]
1.8E-5 = (y)(y)/0.10-y)
This is solved quickly by assuming y<<0.10.
That gives y = 0.0013 (Assumption valid!)
“E” represents “x10^”
More
VOTE