Do you mean 2 Molar? (2M) that would be 2 moles of NaOH per liter of water. Na 23, O 16, H1= 40 grams: 1 mole (one gram molecular weight). Double that per liter= VERY STRONG sodium hydroxide solution that could hurt you.
Do you mean 2 Molar? (2M) that would be 2 moles of NaOH per liter of water. Na 23, O 16, H1= 40 grams: 1 mole (one gram molecular weight). Double that per liter= VERY STRONG sodium hydroxide solution that could hurt you.
6M NaOH solution is made by dissolving 6 mols of NaOH in 1 liter of H2O. NaOH has a molar mass of 39.9997 g/mol so for a 6M solution, we need 240 g NaOH (39.997 x 6) in 1L of H2O. This is an exothermic reaction so use caution.
6M NaOH solution is made by dissolving 6 mols of NaOH in 1 liter of H2O. NaOH has a molar mass of 39.9997 g/mol so for a 6M solution, we need 240 g NaOH (39.997 x 6) in 1L of H2O. This is an exothermic reaction so use caution.
6M NaOH solution means 1 litre (which is [math]1 : dm^3[/math]) of water contains 6 mol of NaOH.
6 mol of NaOH means roughly around 240g of NaOH, so you need to dissolve 240g of NaOH to a liter a water to make a 6M solution.
6M NaOH solution means 1 litre (which is [math]1 : dm^3[/math]) of water contains 6 mol of NaOH.
6 mol of NaOH means roughly around 240g of NaOH, so you need to dissolve 240g of NaOH to a liter a water to make a 6M solution.
More
VOTE
Do you mean 2 Molar? (2M) that would be 2 moles of NaOH per liter of water. Na 23, O 16, H1= 40 grams: 1 mole (one gram molecular weight). Double that per liter= VERY STRONG sodium hydroxide solution that could hurt you.
Do you mean 2 Molar? (2M) that would be 2 moles of NaOH per liter of water. Na 23, O 16, H1= 40 grams: 1 mole (one gram molecular weight). Double that per liter= VERY STRONG sodium hydroxide solution that could hurt you.
More
VOTE
by mass??
5% D = 1.053 g/mL
50.5 % D = 1.53 g/mL
from concentrated solution???
0.505 x 1.53 V1 = 0.05 x 1.053 x 3mL
V1 = 0.2 mL
take the volume from the concentrated solution and dilute it carfully till 3 mL.
%m/v:::::?????
5 g ——100 mL
X————-3 mL
X = 0.15 g
take 0,15 pure NaOH and mix it carefully with wáter till a volume of 3 mL.
by mass??
5% D = 1.053 g/mL
50.5 % D = 1.53 g/mL
from concentrated solution???
0.505 x 1.53 V1 = 0.05 x 1.053 x 3mL
V1 = 0.2 mL
take the volume from the concentrated solution and dilute it carfully till 3 mL.
%m/v:::::?????
5 g ——100 mL
X————-3 mL
X = 0.15 g
take 0,15 pure NaOH and mix it carefully with wáter till a volume of 3 mL.
More
VOTE
6M NaOH solution is made by dissolving 6 mols of NaOH in 1 liter of H2O. NaOH has a molar mass of 39.9997 g/mol so for a 6M solution, we need 240 g NaOH (39.997 x 6) in 1L of H2O. This is an exothermic reaction so use caution.
6M NaOH solution is made by dissolving 6 mols of NaOH in 1 liter of H2O. NaOH has a molar mass of 39.9997 g/mol so for a 6M solution, we need 240 g NaOH (39.997 x 6) in 1L of H2O. This is an exothermic reaction so use caution.
More
VOTE
From stock solution???
from NaOH pure??
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A) from solid NaOH
VM = # mol
0.2 x 0.5 = 0.1 mol NaOH
0.1 mol x 40g/mol = 4 g NaOH
take 4 gram and mix carefully with water till final volume of 500 mL
B) from concentrated solution 40%m/m = 14.3 mol/L
V1M1 = V2M2
14.3 V1 = 0.2 x 0.5
V1 = 7 mL
take 7 mL from the stock solution and dilute till final volume 500 mL(carefully)
From stock solution???
from NaOH pure??
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A) from solid NaOH
VM = # mol
0.2 x 0.5 = 0.1 mol NaOH
0.1 mol x 40g/mol = 4 g NaOH
take 4 gram and mix carefully with water till final volume of 500 mL
B) from concentrated solution 40%m/m = 14.3 mol/L
V1M1 = V2M2
14.3 V1 = 0.2 x 0.5
V1 = 7 mL
take 7 mL from the stock solution and dilute till final volume 500 mL(carefully)
More
VOTE
Here, 1M= 40g NaOH
so 6M= 40 *6=240g NaOH
So,to produce 6M NaOH, you have to take 240g NaOH in a measuring cylinder and add distilled water up to 1 L. The final volume will be 1L.
Here, 1M= 40g NaOH
so 6M= 40 *6=240g NaOH
So,to produce 6M NaOH, you have to take 240g NaOH in a measuring cylinder and add distilled water up to 1 L. The final volume will be 1L.
More
VOTE
Hi there,
Recall the formula for Molarity of a Solution, M = #mols/Volume.
Move things around a bit and see that #mols = M * Volume.
The number of moles of NaOH never changes throughout the dilution, and so we can say that M1V1 = M2V2, where 1 denotes initial and 2 denotes final.
Plug in everything:
(5M)(V1) = (1M)(100mL)
V1 = ((1M)(100mL))/(5M)
V1 = 20 mL of your initial 5M stock solution.
Hi there,
Recall the formula for Molarity of a Solution, M = #mols/Volume.
Move things around a bit and see that #mols = M * Volume.
The number of moles of NaOH never changes throughout the dilution, and so we can say that M1V1 = M2V2, where 1 denotes initial and 2 denotes final.
Plug in everything:
(5M)(V1) = (1M)(100mL)
V1 = ((1M)(100mL))/(5M)
V1 = 20 mL of your initial 5M stock solution.
More
VOTE
See its very simple,
U need to use M1 * V1 = M2 * V2
M1 is the Molarity before dilution (Here 5.5 M)
V1, IS the volume before dilution (Here we need to find that out)
M2 is the Molarity after dilution (Here 1.5 M)
V2 is the volume after dilution (Here 400 mL)
So finally
5.5 * V1 = 1.5 * 400 ml
V1 = 109.09 ML
IF u find that useful than do upvote
See its very simple,
U need to use M1 * V1 = M2 * V2
M1 is the Molarity before dilution (Here 5.5 M)
V1, IS the volume before dilution (Here we need to find that out)
M2 is the Molarity after dilution (Here 1.5 M)
V2 is the volume after dilution (Here 400 mL)
So finally
5.5 * V1 = 1.5 * 400 ml
V1 = 109.09 ML
IF u find that useful than do upvote
More
VOTE