Home > Community > How is the oxidation state of vanadium in [V(CO) 6] - 1?
Upvote

15

Downvote
+ Inorganic chemistry
+ Oxidation
+ Chemistry
+ Vanadium
Posted by
Louis Buff Parry

How is the oxidation state of vanadium in [V(CO) 6] - 1?

Daniel Lynge  Follow
Upvote

VOTE

Downvote
Catherine Shaw  Follow

Vanadium has electron configuration [Ar]4s^23d^3, which means 5 electrons in its valence shell. When you add 6 CO ligands to make the hexacarbonyl, that adds 2X6 = 12 to make a total effective atomic number (EAN) of 17. Many metal carbonyls like to have a full EAN of 18. V(CO)6 can achieve this by a 1 electron reduction to make V(CO)6(1-) with now an EAN of 18. Since the CO’s remain neutral, the 1- charge formally then resides on the V, which thus has a valence of -1.

More

Upvote

VOTE

Downvote