How is the percent ionic character calculated?

Take some compounds to compare their strength:

NaF, MgF2, AlF3, NaBr and NaI

Now, lets look at factors affecting Ionic bond strength:

1. Ionic charge - The greater the product of the ionic charges the stronger the bond
2. Ionic size - The lower the sum of the anion and cation radii, the stronger the bond

Because the cations are Al3+, Mg2+, and Na+
AlF3 > MgF2 > NaF
Because the radius of F- < Br- < I-
NaF > NaBr > NaI
so, in order of increasing bond strength:
NaI < NaBr < NaF < MgF2 < AlF3

So, this is you can determine strongest ionic bond

Thanks for reading

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Sure - for example the Pauling’s equation.

% I.C. = [1-e^(d.el/2)^2]*100

d.el. = difference of electronegativity

There are other ways, of course, for example measuring the bond dipole moment and comparing it with the theoretical moment of a completely ionic bond.

Ionic Character directly relates to electronegativity. The more electronegative your anion is, the more ionic character that molecule will show in its bond.

Relate the relative electronegativity values of these halogens to each other to determine which bond in the most polar, and that will tell you which is the most ionic.

No, there is no compound with a 100% ionic character.

But the equation for finding the ionic character is

In broad terms the percent ionic character of a compound of two atoms is proportional to the electro-negativity (EN) difference between the two atoms. This follows the Pauling equation. The relationship is sigmoid in form and goes from 0% at 0 EN to almost 100% at EN of 3.5.

There is a very useful Excel spreadsheet to make the calculation at:

https://c7chemistry.wikispaces.com/.../percent%20ionic%20character%20...

It also lists the EN of various atoms.

The ability to lose electrons (metals) or gain them (non-metals) and the behavior it exhibits while doing that.

Percent ionic character can be approximated from the difference in electronegativity, ΔEN.

% ionic character = 100(1 - e^(-ΔEN² / 4))

From L. Pauling

Well the difference in electronegativity for all of those in order are, 3, 2.18, 1.98 and 1.68, so the only molecular/covalent(and it’s polar) lithium halogen within these 4 is Lithium Iodide(LiI) and the most Ionic is Lithium Fluoride(LiF).