I'm quite sure you meant alkaline iodide sodium azide solution. The preaparation of this reagent is given here:
To prepare this reagent, take 700 g of potassium hydroxide/500 g of
sodium hydroxide and add 150 g of potassium iodide/ 135 g of sodium
iodide and dissolve in freshly boiled and cooled water and make up tp
1000 ml.
Dissolve 10 g of sodium azide in 40 ml distilled water and add this
solution with continuous stirring to the cool alkaline iodide prepared
previously.
I'm quite sure you meant alkaline iodide sodium azide solution. The preaparation of this reagent is given here:
To prepare this reagent, take 700 g of potassium hydroxide/500 g of sodium hydroxide and add 150 g of potassium iodide/ 135 g of sodium iodide and dissolve in freshly boiled and cooled water and make up tp 1000 ml.
Dissolve 10 g of sodium azide in 40 ml distilled water and add this solution with continuous stirring to the cool alkaline iodide prepared previously.
@NilayGosh I calculated that the molar ratio between the Iodide and the Hydroxide is 1:1. And then I calculated that the ratio of the masses between NaI and NaOH should be 3.75:1. However, in the thing you sent me and in other labs, they always take more NaOH than NaI, and its actually with the same ratio, just inverted. Could you explain this to me please?More
The link you sent in your answer sometimes uses alkaline iodide azide and sometimes alkaline iodide sodium azide. I cant tell if theyre using them interchangeably or if they are referring to two different things.More
I'm quite sure you meant alkaline iodide sodium azide solution. The preaparation of this reagent is given here:
I'm quite sure you meant alkaline iodide sodium azide solution. The preaparation of this reagent is given here:
More
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