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Substance Q is a hydrocarbon. When 1.00 g of Q is completely burned, 3.22 g of carbon dioxide is produced. What could be the identity of Q? A cyclohexene B cyclopentane C ethene D pentane?
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Posted by
Lore Murdock
Substance Q is a hydrocarbon. When 1.00 g of Q is completely burned, 3.22 g of carbon dioxide is produced. What could be the identity of Q? A cyclohexene B cyclopentane C ethene D pentane?
Well, this isn't a compound but it would help to reduce the amount of carbon dioxide in the atmosphere of Venus.
Add hydrogen into the atmosphere with an iron aerosol to catalyse the reaction between the carbon dioxide and the hydrogen. This would result in H2O and carbon which would likely take the form graphite. Although it require a lot of hydrogen specifically 4×10^19 kg of hydrogen and there is a risk that, due to the density of Venus' atmosphere the carbon would float near the top cloud layers and darken the atmosphere resulting in an increase of heat absorbtion.
There is also the magnesium and calcium, like you said, that could be added to the atmosphere that would form carbonates like you said, roughly 8 X 10^20 kg would be required for calcium and 5 x 10^20 kg required for magnesium. Although hydrogen is a lot easier to get hold of than magnesium or calcium is.
There's also lithium nitride which, after the reaction, forms a solid compound which would fall to the surface. Although it is a violently exothermic reaction.
That's the only other compound I could find. Hope that helps!
Well, this isn't a compound but it would help to reduce the amount of carbon dioxide in the atmosphere of Venus.
Add hydrogen into the atmosphere with an iron aerosol to catalyse the reaction between the carbon dioxide and the hydrogen. This would result in H2O and carbon which would likely take the form graphite. Although it require a lot of hydrogen specifically 4×10^19 kg of hydrogen and there is a risk that, due to the density of Venus' atmosphere the carbon would float near the top cloud layers and darken the atmosphere resulting in an increase of heat absorbtion.
There is also the magnesium and calcium, like you said, that could be added to the atmosphere that would form carbonates like you said, roughly 8 X 10^20 kg would be required for calcium and 5 x 10^20 kg required for magnesium. Although hydrogen is a lot easier to get hold of than magnesium or calcium is.
There's also lithium nitride which, after the reaction, forms a solid compound which would fall to the surface. Although it is a violently exothermic reaction.
That's the only other compound I could find. Hope that helps!
Well, this isn't a compound but it would help to reduce the amount of carbon dioxide in the atmosphere of Venus.
Add hydrogen into the atmosphere with an iron aerosol to catalyse the reaction between the carbon dioxide and the hydrogen. This would result in H2O and carbon which would likely take the form graphite. Although it require a lot of hydrogen specifically 4×10^19 kg of hydrogen and there is a risk that, due to the density of Venus' atmosphere the carbon would float near the top cloud layers and darken the atmosphere resulting in an increase of heat absorbtion.
There is also the magnesium and calcium, like you said, that could be added to the atmosphere that would form carbonates like you said, roughly 8 X 10^20 kg would be required for calcium and 5 x 10^20 kg required for magnesium. Although hydrogen is a lot easier to get hold of than magnesium or calcium is.
There's also lithium nitride which, after the reaction, forms a solid compound which would fall to the surface. Although it is a violently exothermic reaction.
That's the only other compound I could find. Hope that helps!
Well, this isn't a compound but it would help to reduce the amount of carbon dioxide in the atmosphere of Venus.
Add hydrogen into the atmosphere with an iron aerosol to catalyse the reaction between the carbon dioxide and the hydrogen. This would result in H2O and carbon which would likely take the form graphite. Although it require a lot of hydrogen specifically 4×10^19 kg of hydrogen and there is a risk that, due to the density of Venus' atmosphere the carbon would float near the top cloud layers and darken the atmosphere resulting in an increase of heat absorbtion.
There is also the magnesium and calcium, like you said, that could be added to the atmosphere that would form carbonates like you said, roughly 8 X 10^20 kg would be required for calcium and 5 x 10^20 kg required for magnesium. Although hydrogen is a lot easier to get hold of than magnesium or calcium is.
There's also lithium nitride which, after the reaction, forms a solid compound which would fall to the surface. Although it is a violently exothermic reaction.
That's the only other compound I could find. Hope that helps!
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The right answer is A) cyclohexene.
Solution:
Mass of carbon dioxide (CO2) produced from 1.00 g of hydrocarbon Q = 3.22 g
Molar mass of CO2 = 12 + 16*2 = 44 g/mol
Moles in 3.22 g of CO2 = 3.22/44 = 0.0732 mol
1 mole of carbon (C) gives 1 mole of CO2 on complete combustion.
Moles of carbon in 1.00 g of Q = 0.0732 mol
Mass of carbon in 1.00 g of Q = 12 g x 0.0732 = 0.878 g
Mass of hydrogen in 1.00 g of Q = 1.00 g - 0.878 g = 0.122 g
Moles of hydrogen atoms in 1.00 g of Q = 0.122/1 = 0.122 mol
Molar ratio of carbon to hydrogen in Q = 0.0732 : 0.122 = 1 : 0.122/0.0732
= 1 : 1.67 = 3 : 5
So, the empirical formula of Q = C3H5
But C3H5 is the empirical formula of cyclohexene, whose molecular formula is C6H10.
Hence the hydrocarbon Q is cyclohexene, C6H10.
The right answer is A) cyclohexene.
Solution:
Mass of carbon dioxide (CO2) produced from 1.00 g of hydrocarbon Q = 3.22 g
Molar mass of CO2 = 12 + 16*2 = 44 g/mol
Moles in 3.22 g of CO2 = 3.22/44 = 0.0732 mol
1 mole of carbon (C) gives 1 mole of CO2 on complete combustion.
Moles of carbon in 1.00 g of Q = 0.0732 mol
Mass of carbon in 1.00 g of Q = 12 g x 0.0732 = 0.878 g
Mass of hydrogen in 1.00 g of Q = 1.00 g - 0.878 g = 0.122 g
Moles of hydrogen atoms in 1.00 g of Q = 0.122/1 = 0.122 mol
Molar ratio of carbon to hydrogen in Q = 0.0732 : 0.122 = 1 : 0.122/0.0732
= 1 : 1.67 = 3 : 5
So, the empirical formula of Q = C3H5
But C3H5 is the empirical formula of cyclohexene, whose molecular formula is C6H10.
Hence the hydrocarbon Q is cyclohexene, C6H10.
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