Comes up to around 1.72. I think that there's something wrong with the calculation of the concentration of sodium acetate.
a) 0.095M * 0.0231L = 2.1945 * 10^-3 mol of sodium acetate b) conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/vol of CH3COONa conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/0.0467L conc of CH3COONa at equivalence point = 0.047M
vol of CH3COONa = Vol of acetic acid + Vol of NaOH vol of CH3COONa = 0.025L + (2.1945*10^-3)/0.101M vol of CH3COONa at equivalence point = 0.0467L
I am not sure if this makes sense... this is the first introductory chemistry module I have taken in a few years and I have found it pretty difficult to wrap my head around concepts like pH, pKa and the like.
Comes up to around 1.72. I think that there's something wrong with the calculation of the concentration of sodium acetate.
a) 0.095M * 0.0231L = 2.1945 * 10^-3 mol of sodium acetate b) conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/vol of CH3COONa conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/0.0467L conc of CH3COONa at equivalence point = 0.047M
vol of CH3COONa = Vol of acetic acid + Vol of NaOH vol of CH3COONa = 0.025L + (2.1945*10^-3)/0.101M vol of CH3COONa at equivalence point = 0.0467L
I am not sure if this makes sense... this is the first introductory chemistry module I have taken in a few years and I have found it pretty difficult to wrap my head around concepts like pH, pKa and the like.
c) Then using the equation pH = 1/2pKw + 1/2pKa + 1/2logc, calculate the pH at the equivalence point. (my pH comes out to about 1.86 here which is totally off the expected value)
c) Then using the equation pH = 1/2pKw + 1/2pKa + 1/2logc, calculate the pH at the equivalence point. (my pH comes out to about 1.86 here which is totally off the expected value)
Oh... I get it now. No wonder I've been getting such a low pH value! I got mixed up with the two. Just another question - How do I calculate the total concentration of the following:
What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
Oh... I get it now. No wonder I've been getting such a low pH value! I got mixed up with the two. Just another question - How do I calculate the total concentration of the following:
What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
This is ambiguous, as it doesn't state total concentration of what.
But in the context of buffers we often say things like "0.1 M buffer" and it is intended to mean "sum of concentrations of HAcetate and Acetate- is 0.1 M".
What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
This is ambiguous, as it doesn't state total concentration of what.
But in the context of buffers we often say things like "0.1 M buffer" and it is intended to mean "sum of concentrations of HAcetate and Acetate- is 0.1 M".
This is not answer to the question "what is pKw"?
Do you understand the difference between Kw and pKw?
This is not answer to the question "what is pKw"?
Do you understand the difference between Kw and pKw?
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Comes up to around 1.72. I think that there's something wrong with the calculation of the concentration of sodium acetate.
a) 0.095M * 0.0231L = 2.1945 * 10^-3 mol of sodium acetate
b) conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/vol of CH3COONa
conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/0.0467L
conc of CH3COONa at equivalence point = 0.047M
vol of CH3COONa = Vol of acetic acid + Vol of NaOH
vol of CH3COONa = 0.025L + (2.1945*10^-3)/0.101M
vol of CH3COONa at equivalence point = 0.0467L
I am not sure if this makes sense... this is the first introductory chemistry module I have taken in a few years and I have found it pretty difficult to wrap my head around concepts like pH, pKa and the like.
Comes up to around 1.72. I think that there's something wrong with the calculation of the concentration of sodium acetate.
a) 0.095M * 0.0231L = 2.1945 * 10^-3 mol of sodium acetate
b) conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/vol of CH3COONa
conc of CH3COONa at equivalence point = (2.1945 * 10^-3 mol)/0.0467L
conc of CH3COONa at equivalence point = 0.047M
vol of CH3COONa = Vol of acetic acid + Vol of NaOH
vol of CH3COONa = 0.025L + (2.1945*10^-3)/0.101M
vol of CH3COONa at equivalence point = 0.0467L
I am not sure if this makes sense... this is the first introductory chemistry module I have taken in a few years and I have found it pretty difficult to wrap my head around concepts like pH, pKa and the like.
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That's not what I got, list all values you used.
That's not what I got, list all values you used.
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What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
What is the total concentration (mol/L) of 3.4g of sodium acetate mixed with 30mL of 1.0M acetic acid?
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VOTE
This is ambiguous, as it doesn't state total concentration of what.
But in the context of buffers we often say things like "0.1 M buffer" and it is intended to mean "sum of concentrations of HAcetate and Acetate- is 0.1 M".
This is ambiguous, as it doesn't state total concentration of what.
But in the context of buffers we often say things like "0.1 M buffer" and it is intended to mean "sum of concentrations of HAcetate and Acetate- is 0.1 M".
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VOTE
What is pKw?
What is pKw?
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