YOU ARE RIGHT @GERLINDE ROSKAM. Thanks for correction. The depth of the soil is really 3 m, NOT 0.3 m as I calculated. I am sorry for my mistake. Correct result is The mass of P sorbed per ha (depth 300 cm) 2.801.104 kg/ha. I appologize for my mistake . Best regards Vit
YOU ARE RIGHT @GERLINDE ROSKAM. Thanks for correction. The depth of the soil is really 3 m, NOT 0.3 m as I calculated. I am sorry for my mistake. Correct result is The mass of P sorbed per ha (depth 300 cm) 2.801.104 kg/ha. I appologize for my mistake . Best regards Vit
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm): V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3 bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3 m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg Sorption capacity of soil for P: 667 mg.kg-1 the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P. Regards Vit
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm): V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3 bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3 m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg Sorption capacity of soil for P: 667 mg.kg-1 the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P. Regards Vit
Vit Mateju Yes I agree. it is, Area, 1 ha = 10,000 m^2; depth, 0.3 m = 300 cm; volume of soil in one ha, V = 10,000 m^2 x 0.3 m = 3,000 m^3 bulk density, 1.4 g/cm^3 = 1,400 kg/m^3 Weight of soil in 1 ha = 3,000 m^3 X 1,400 kg/m^3 = 4,200,000 kg/ha So, P sorption capacity 667 mg/kg => 667 mg/kg X 4,200,000 kg/ha = 2,801,400,000 mg/ha = 2.80 X 10^3 kg/ha
Vit Mateju Yes I agree. it is, Area, 1 ha = 10,000 m^2; depth, 0.3 m = 300 cm; volume of soil in one ha, V = 10,000 m^2 x 0.3 m = 3,000 m^3 bulk density, 1.4 g/cm^3 = 1,400 kg/m^3 Weight of soil in 1 ha = 3,000 m^3 X 1,400 kg/m^3 = 4,200,000 kg/ha So, P sorption capacity 667 mg/kg => 667 mg/kg X 4,200,000 kg/ha = 2,801,400,000 mg/ha = 2.80 X 10^3 kg/ha
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm): V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3 bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3 m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg Sorption capacity of soil for P: 667 mg.kg-1 the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P. Regards Vit
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm): V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3 bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3 m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg Sorption capacity of soil for P: 667 mg.kg-1 the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P. Regards Vit
Thank you Vit, that was my initial result! thank you for confirming
Thank you Vit, that was my initial result! thank you for confirming
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YOU ARE RIGHT @GERLINDE ROSKAM. Thanks for correction. The depth of the soil is really 3 m, NOT 0.3 m as I calculated. I am sorry for my mistake.
Correct result is The mass of P sorbed per ha (depth 300 cm) 2.801.104 kg/ha.
I appologize for my mistake .
Best regards
Vit
YOU ARE RIGHT @GERLINDE ROSKAM. Thanks for correction. The depth of the soil is really 3 m, NOT 0.3 m as I calculated. I am sorry for my mistake.
Correct result is The mass of P sorbed per ha (depth 300 cm) 2.801.104 kg/ha.
I appologize for my mistake .
Best regards
Vit
More
VOTE
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm):
V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3
bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3
m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg
Sorption capacity of soil for P: 667 mg.kg-1
the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P.
Regards
Vit
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm):
V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3
bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3
m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg
Sorption capacity of soil for P: 667 mg.kg-1
the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P.
Regards
Vit
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The mass of P sorbed per ha (depth 300 cm) 2.801.103 kg/ha
Regards
Vit
The mass of P sorbed per ha (depth 300 cm) 2.801.103 kg/ha
Regards
Vit
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Vit Mateju Yes I agree.
it is,
Area, 1 ha = 10,000 m^2;
depth, 0.3 m = 300 cm;
volume of soil in one ha, V = 10,000 m^2 x 0.3 m = 3,000 m^3
bulk density, 1.4 g/cm^3 = 1,400 kg/m^3
Weight of soil in 1 ha = 3,000 m^3 X 1,400 kg/m^3 = 4,200,000 kg/ha
So, P sorption capacity 667 mg/kg => 667 mg/kg X 4,200,000 kg/ha
= 2,801,400,000 mg/ha
= 2.80 X 10^3 kg/ha
Vit Mateju Yes I agree.
it is,
Area, 1 ha = 10,000 m^2;
depth, 0.3 m = 300 cm;
volume of soil in one ha, V = 10,000 m^2 x 0.3 m = 3,000 m^3
bulk density, 1.4 g/cm^3 = 1,400 kg/m^3
Weight of soil in 1 ha = 3,000 m^3 X 1,400 kg/m^3 = 4,200,000 kg/ha
So, P sorption capacity 667 mg/kg => 667 mg/kg X 4,200,000 kg/ha
= 2,801,400,000 mg/ha
= 2.80 X 10^3 kg/ha
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I'd say 300 cm is 3 meter, not 0.3 m ...
I'd say 300 cm is 3 meter, not 0.3 m ...
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The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm):
V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3
bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3
m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg
Sorption capacity of soil for P: 667 mg.kg-1
the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P.
Regards
Vit
The mass of soil, area of 1 ha (= 10,000 m2), depth 0.3 m (= 300 cm):
V (volume of soil) = 10,000 m2 * 0.3 m = 3,000 m3
bulk density 1.4 g.cm-3 is equal to 1,400 kg.m-3
m (mass of soil) = 3,000 m3 * 1,400 kg.m-3 = 4.2*106 kg
Sorption capacity of soil for P: 667 mg.kg-1
the total mass of sorbed P is 4.2*106 kg * 667 mg.kg-1 = 2.801.109 mg = 2.801.103 kg of P.
Regards
Vit
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VOTE