FeCl3 reacts with NaOH to form Fe(OH)3 and NaCl. In other words, iron(III) chloride reacts with sodium hydroxide to form iron(III) hydroxide and sodium chloride.
The balanced equation for the reaction between FeCl3 and NaOH is FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl. Since iron(III) chloride and sodium chloride are soluble in water, but not iron(III) hydroxide, the reaction causes a solid to be precipitated. As iron(III) hydroxide is brown, a brown precipitate is formed. Hence, this is known as a precipitation reaction.
FeCl3 reacts with NaOH to form Fe(OH)3 and NaCl. In other words, iron(III) chloride reacts with sodium hydroxide to form iron(III) hydroxide and sodium chloride.
The balanced equation for the reaction between FeCl3 and NaOH is FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl. Since iron(III) chloride and sodium chloride are soluble in water, but not iron(III) hydroxide, the reaction causes a solid to be precipitated. As iron(III) hydroxide is brown, a brown precipitate is formed. Hence, this is known as a precipitation reaction.
Sodium hydroxide reacts very strongly with hydrochloric acid to form NaCl and water. That so much energy is released tells us that though the reverse reaction can occur, the equilibrium very much favors what we think of as the forward, natural direction. So a short answer to your question would be "not significantly."
Sodium hydroxide reacts very strongly with hydrochloric acid to form NaCl and water. That so much energy is released tells us that though the reverse reaction can occur, the equilibrium very much favors what we think of as the forward, natural direction. So a short answer to your question would be "not significantly."
The first consideration I can make is that whoever asked the question does not know what he is talking about. Speaking about "equal volume", being the two chemicals solid, it is a no sense. Moreover if you consider the volume of an aqueous solution of the two chemicals you have to know the concentration of NaOH and FeCl2. Depending on the ratio between the two chemicals you can have a precipitate of Fe(OH)2 [ferrum hydroxyde (II)] or in excess of NaOH you can have a complex like this Na [Fe(OH)3] or other ferrous salt.
The first consideration I can make is that whoever asked the question does not know what he is talking about. Speaking about "equal volume", being the two chemicals solid, it is a no sense. Moreover if you consider the volume of an aqueous solution of the two chemicals you have to know the concentration of NaOH and FeCl2. Depending on the ratio between the two chemicals you can have a precipitate of Fe(OH)2 [ferrum hydroxyde (II)] or in excess of NaOH you can have a complex like this Na [Fe(OH)3] or other ferrous salt.
Both are soluble in water. Acetone goes to the enol form in the presence of strong alkali, and condensation occurs, making diacetone alcohol. I think condensation continues further. You need to consult an organic chemistry book for properties of methyl ketones.
Both are soluble in water. Acetone goes to the enol form in the presence of strong alkali, and condensation occurs, making diacetone alcohol. I think condensation continues further. You need to consult an organic chemistry book for properties of methyl ketones.
Since NaOH is a base, any acid will react with it. Additionally a variety of different metal ions will form insoluble hydroxide precipitates with it.
Since NaOH is a base, any acid will react with it. Additionally a variety of different metal ions will form insoluble hydroxide precipitates with it.
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The reaction of iron 3 (presumably, Fe(3+) and sodium hydroxide (NaOH) is shown below.
Fe(3+) + 3 NaOH → Fe(OH)3 + 3 Na(1+)
The counter ions for Fe(3+) were not stated but if they were Cl-, for example, the product would NaCl.
The reaction of iron 3 (presumably, Fe(3+) and sodium hydroxide (NaOH) is shown below.
Fe(3+) + 3 NaOH → Fe(OH)3 + 3 Na(1+)
The counter ions for Fe(3+) were not stated but if they were Cl-, for example, the product would NaCl.
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A re d brown ppt of Iron (111) hydroxide forms, along with sodium chroride solution.
FeCl3 (aq) + 3 NaOH (aq) --> Fe (OH)3 (s) + 3NaCl (aq)
A re d brown ppt of Iron (111) hydroxide forms, along with sodium chroride solution.
FeCl3 (aq) + 3 NaOH (aq) --> Fe (OH)3 (s) + 3NaCl (aq)
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FeCl3 reacts with NaOH to form Fe(OH)3 and NaCl. In other words, iron(III) chloride reacts with sodium hydroxide to form iron(III) hydroxide and sodium chloride.
The balanced equation for the reaction between FeCl3 and NaOH is FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl. Since iron(III) chloride and sodium chloride are soluble in water, but not iron(III) hydroxide, the reaction causes a solid to be precipitated. As iron(III) hydroxide is brown, a brown precipitate is formed. Hence, this is known as a precipitation reaction.
FeCl3 reacts with NaOH to form Fe(OH)3 and NaCl. In other words, iron(III) chloride reacts with sodium hydroxide to form iron(III) hydroxide and sodium chloride.
The balanced equation for the reaction between FeCl3 and NaOH is FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl. Since iron(III) chloride and sodium chloride are soluble in water, but not iron(III) hydroxide, the reaction causes a solid to be precipitated. As iron(III) hydroxide is brown, a brown precipitate is formed. Hence, this is known as a precipitation reaction.
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Sodium hydroxide reacts very strongly with hydrochloric acid to form NaCl and water. That so much energy is released tells us that though the reverse reaction can occur, the equilibrium very much favors what we think of as the forward, natural direction. So a short answer to your question would be "not significantly."
Sodium hydroxide reacts very strongly with hydrochloric acid to form NaCl and water. That so much energy is released tells us that though the reverse reaction can occur, the equilibrium very much favors what we think of as the forward, natural direction. So a short answer to your question would be "not significantly."
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The first consideration I can make is that whoever asked the question does not know what he is talking about. Speaking about "equal volume", being the two chemicals solid, it is a no sense. Moreover if you consider the volume of an aqueous solution of the two chemicals you have to know the concentration of NaOH and FeCl2.
Depending on the ratio between the two chemicals you can have a precipitate of Fe(OH)2 [ferrum hydroxyde (II)] or in excess of NaOH you can have a complex like this Na [Fe(OH)3] or other ferrous salt.
The first consideration I can make is that whoever asked the question does not know what he is talking about. Speaking about "equal volume", being the two chemicals solid, it is a no sense. Moreover if you consider the volume of an aqueous solution of the two chemicals you have to know the concentration of NaOH and FeCl2.
Depending on the ratio between the two chemicals you can have a precipitate of Fe(OH)2 [ferrum hydroxyde (II)] or in excess of NaOH you can have a complex like this Na [Fe(OH)3] or other ferrous salt.
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Both are soluble in water. Acetone goes to the enol form in the presence of strong alkali, and condensation occurs, making diacetone alcohol. I think condensation continues further. You need to consult an organic chemistry book for properties of methyl ketones.
Both are soluble in water. Acetone goes to the enol form in the presence of strong alkali, and condensation occurs, making diacetone alcohol. I think condensation continues further. You need to consult an organic chemistry book for properties of methyl ketones.
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