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What happens when copper reacts with concentrated nitric acid and dilute nitric acid?
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Posted by
Kai Rabenstein
What happens when copper reacts with concentrated nitric acid and dilute nitric acid?
It forms Copper II Nitrate Cu(NO3)2 if reacted with nitric acid in any concentration - it’s not the usual metal - acid reaction though, as it produces oxides of Nitrogen and water rather than hydrogen, due to the NO3- anions oxidising the metal.
In dilute concentrations, nitrogen monoxide is produced:
3Cu + 8HNO3 ⟶ 3Cu(NO3)2 + 2NO + 4 H2O
and in concentrated form, nitrogen dioxide is given off:
It forms Copper II Nitrate Cu(NO3)2 if reacted with nitric acid in any concentration - it’s not the usual metal - acid reaction though, as it produces oxides of Nitrogen and water rather than hydrogen, due to the NO3- anions oxidising the metal.
In dilute concentrations, nitrogen monoxide is produced:
3Cu + 8HNO3 ⟶ 3Cu(NO3)2 + 2NO + 4 H2O
and in concentrated form, nitrogen dioxide is given off:
It forms Copper II Nitrate Cu(NO3)2 if reacted with nitric acid in any concentration - it’s not the usual metal - acid reaction though, as it produces oxides of Nitrogen and water rather than hydrogen, due to the NO3- anions oxidising the metal.
In dilute concentrations, nitrogen monoxide is produced:
3Cu + 8HNO3 ⟶ 3Cu(NO3)2 + 2NO + 4 H2O
and in concentrated form, nitrogen dioxide is given off:
Cu + 4HNO3 ⟶ Cu(NO3)2 + 2NO2 + 2H2O
It forms Copper II Nitrate Cu(NO3)2 if reacted with nitric acid in any concentration - it’s not the usual metal - acid reaction though, as it produces oxides of Nitrogen and water rather than hydrogen, due to the NO3- anions oxidising the metal.
In dilute concentrations, nitrogen monoxide is produced:
3Cu + 8HNO3 ⟶ 3Cu(NO3)2 + 2NO + 4 H2O
and in concentrated form, nitrogen dioxide is given off:
Cu + 4HNO3 ⟶ Cu(NO3)2 + 2NO2 + 2H2O
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