The helium molecule ion, He2(+), has altogether three electrons. Out of these three electrons, 2 occupy the lower bonding molecular orbital (MO) and the remaining one occupy the higher antibonding molecular orbital.
Bond order = 1/2( no. of electrons in the bonding MO - no. of electrons in the antibonding MO = 1/2 (2–1) = 1/2 = 0.5
The bond order of the neutral He2 molecule is zero and so it has no existence at the normal conditions.
The helium molecule ion, He2(+), has altogether three electrons. Out of these three electrons, 2 occupy the lower bonding molecular orbital (MO) and the remaining one occupy the higher antibonding molecular orbital.
Bond order = 1/2( no. of electrons in the bonding MO - no. of electrons in the antibonding MO = 1/2 (2–1) = 1/2 = 0.5
The bond order of the neutral He2 molecule is zero and so it has no existence at the normal conditions.
The bond lengths are inverse to the bond order,so the order us F2+
The bond lengths are inverse to the bond order,so the order us F2+
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JUST REMEMBER THIS SIMPLE TRICK
Z= ADDITION OF ATOMIC NUMBERS OF ALL ATOMS IN A MOLECULE
Z = 8 9 10 11 12 13 14 15 16 17 18 19 20
BO= 0 0.5 1 1.5 2 2.5 3 2.5 2 1.5 1 0.5 0
JUST REMEMBER BO OF 14 IS 3 , ABOVE OR BELOW 14 JUST KEEP DECREASING BY 0.5
HENCE THE FINAL IS
N2 Z=14 ……3
N2- Z=15…….2.5
N2+ Z=13…….2
HOPE IT HELPED U
JUST REMEMBER THIS SIMPLE TRICK
Z= ADDITION OF ATOMIC NUMBERS OF ALL ATOMS IN A MOLECULE
Z = 8 9 10 11 12 13 14 15 16 17 18 19 20
BO= 0 0.5 1 1.5 2 2.5 3 2.5 2 1.5 1 0.5 0
JUST REMEMBER BO OF 14 IS 3 , ABOVE OR BELOW 14 JUST KEEP DECREASING BY 0.5
HENCE THE FINAL IS
N2 Z=14 ……3
N2- Z=15…….2.5
N2+ Z=13…….2
HOPE IT HELPED U
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Fluorine molecule,F2, has 18 electrons in total..it has 10 bonding electrons and 8 anti bonding electrons ..therefore its bonding order is 1.
Fluorine molecule,F2, has 18 electrons in total..it has 10 bonding electrons and 8 anti bonding electrons ..therefore its bonding order is 1.
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Hi guys let me tell u one short trick for finding bond order…
First of all for the given molecule add up the total no of electrons present in that molecule..
For example here in N2 we have 7+7 =14 electrons.
Now remember this table..
ELECTRONS = BOND ORDER
10 = 1
11 = 1.5
12= 2
13= 2.5
14=3
15=2.5
16=2
17=1.5
18=1
Thank u..plz remember this short trick table for objectives..now kindly solve examples in your +2 book.
Hi guys let me tell u one short trick for finding bond order…
First of all for the given molecule add up the total no of electrons present in that molecule..
For example here in N2 we have 7+7 =14 electrons.
Now remember this table..
ELECTRONS = BOND ORDER
10 = 1
11 = 1.5
12= 2
13= 2.5
14=3
15=2.5
16=2
17=1.5
18=1
Thank u..plz remember this short trick table for objectives..now kindly solve examples in your +2 book.
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The bond order of He2(+) is 0.5.
The helium molecule ion, He2(+), has altogether three electrons. Out of these three electrons, 2 occupy the lower bonding molecular orbital (MO) and the remaining one occupy the higher antibonding molecular orbital.
Bond order = 1/2( no. of electrons in the bonding MO - no. of electrons in the antibonding MO = 1/2 (2–1) = 1/2 = 0.5
The bond order of the neutral He2 molecule is zero and so it has no existence at the normal conditions.
The bond order of He2(+) is 0.5.
The helium molecule ion, He2(+), has altogether three electrons. Out of these three electrons, 2 occupy the lower bonding molecular orbital (MO) and the remaining one occupy the higher antibonding molecular orbital.
Bond order = 1/2( no. of electrons in the bonding MO - no. of electrons in the antibonding MO = 1/2 (2–1) = 1/2 = 0.5
The bond order of the neutral He2 molecule is zero and so it has no existence at the normal conditions.
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The bond lengths are inverse to the bond order, so the order is F2+ < F2 .There is 1 unpaired electron in F2+, 0 unpaired electrons in F2.
The bond lengths are inverse to the bond order, so the order is F2+ < F2 .There is 1 unpaired electron in F2+, 0 unpaired electrons in F2.
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One
Because structure formed will be like this
Br-Br
Since there is only one bond btw them its bond order is one
Hope it helps
Please upvote , follow ,share to motivate me
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One
Because structure formed will be like this
Br-Br
Since there is only one bond btw them its bond order is one
Hope it helps
Please upvote , follow ,share to motivate me
✌️✌️✌️
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Total number of electrons in F2+ is 17
By filling of orbital according to MOT
Total number of electrons in F2+ is 17
By filling of orbital according to MOT
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Bond order of CN is 2.5.
It is found by doing molecular electronic configuration.
Formua——— 1/2(no. Of bonding electron - no. Of non bonding electron)
Bond order of CN is 2.5.
It is found by doing molecular electronic configuration.
Formua——— 1/2(no. Of bonding electron - no. Of non bonding electron)
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