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What is sulphur’s hybridization in sulphur hexafluoride?
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What is sulphur’s hybridization in sulphur hexafluoride?
In SOF4 also called thionyl fluoride , in this molecule sulphur is a central metal atom having atomic number 16 ( second member of group 16) and it is surrounded by 4 Fluorine atoms and one oxygen atom. It makes 5- sigma bonds and 1-π bond. Let's explain its hybridization with the following diagrammatic representation :
In SOF4 also called thionyl fluoride , in this molecule sulphur is a central metal atom having atomic number 16 ( second member of group 16) and it is surrounded by 4 Fluorine atoms and one oxygen atom. It makes 5- sigma bonds and 1-π bond. Let's explain its hybridization with the following diagrammatic representation :
The hybridization of sulfur in SOF4 is sp3d. Sulphur forms five sigma bonds and one pi-bond. For five sigma bonds sulfur needs five hybrid orbitals. The pi-bond is formed with oxygen by the unhybridized orbital of sulfur
The structure is trigonal bipyramidal in which two fluorine atoms occupy the axial positions, and the other two fluorine atoms occupy the equatorial positions. Oxygen atom is also present in the equatorial position with a double bond.
The hybridization of sulfur in SOF4 is sp3d. Sulphur forms five sigma bonds and one pi-bond. For five sigma bonds sulfur needs five hybrid orbitals. The pi-bond is formed with oxygen by the unhybridized orbital of sulfur
The structure is trigonal bipyramidal in which two fluorine atoms occupy the axial positions, and the other two fluorine atoms occupy the equatorial positions. Oxygen atom is also present in the equatorial position with a double bond.
In SOF4 also called thionyl fluoride , in this molecule sulphur is a central metal atom having atomic number 16 ( second member of group 16) and it is surrounded by 4 Fluorine atoms and one oxygen atom. It makes 5- sigma bonds and 1-π bond. Let's explain its hybridization with the following diagrammatic representation :
In SOF4 also called thionyl fluoride , in this molecule sulphur is a central metal atom having atomic number 16 ( second member of group 16) and it is surrounded by 4 Fluorine atoms and one oxygen atom. It makes 5- sigma bonds and 1-π bond. Let's explain its hybridization with the following diagrammatic representation :
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The hybridization of sulfur in SOF4 is sp3d. Sulphur forms five sigma bonds and one pi-bond. For five sigma bonds sulfur needs five hybrid orbitals. The pi-bond is formed with oxygen by the unhybridized orbital of sulfur
The structure is trigonal bipyramidal in which two fluorine atoms occupy the axial positions, and the other two fluorine atoms occupy the equatorial positions. Oxygen atom is also present in the equatorial position with a double bond.
The hybridization of sulfur in SOF4 is sp3d. Sulphur forms five sigma bonds and one pi-bond. For five sigma bonds sulfur needs five hybrid orbitals. The pi-bond is formed with oxygen by the unhybridized orbital of sulfur
The structure is trigonal bipyramidal in which two fluorine atoms occupy the axial positions, and the other two fluorine atoms occupy the equatorial positions. Oxygen atom is also present in the equatorial position with a double bond.
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