What is sulphuric acid to barium carbonate neutralization state in kg?

Barium sulfate is used because it is extremely insoluble. Barium is a heavy metal, so if it dissolved, a person would absorb barium ions into their body and get heavy metal poisoning. As barium sulfate does not dissolve, it passes straight through the body, safely.

Barium carbonate would react with the hydrochloric acid in the stomach. One of the products of this reaction would be barium chloride which is soluble and you would be poisoned from the barium as the body could readily absorb it.

• It can be.
• Barium chloride is a salt.
• Dilute sulfuric acid as the name suggests is an acid.
• It could be a displacement reaction.
• The products could be a white precipitate of barium sulfate and aqueous solution of hydrogen chloride.
• The balanced chemical equation is as follows

BaCl2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2 HCl (aq)

The valency of sulphur is -2

-ve charge

-1:

•Ch3coo

•OH

•NO3

•HSo4

•HCo3

-2:

•Co3

•So4

-3

•Po4

Generally 98% sulfuric acid is sold in the market so use dilution formula, say for example we wish to prepare 100 ml of 10% volume by volume solution

then

98% X ml? = 10 % X 100

X ml= 1000/98 = 10.20ml

now add 89.8ml of water in 100 ml volumetric flask then add 10.20 ml sulfuric acid into it.

Note: sulfuric is very dangerous acid if contacted, so please strictly follow lab safety measures while preparing above mentioned 10% solution.

In dilute solution
[math]Ba(OH)_2 + H_2SO_4 = BaSO_4 + 2H_2O[/math]
Barium sulphate is insoluble and precipitates.

If the sulphuric acid is very strong the barium sulphate does not precipitate. In fact barium sulphate can be dissolved in concentrated sulphuric acid.

Barium sulfate is as soluble as a brick in aqueous solution. And so we take soluble barium chloride, or barium nitrate, and add 1 equiv sulfuric acid to give stoichiometric barium sulfate according to the following reaction …

[math]BaCl_{2}(aq) + H_{2}SO_{4}(aq) longrightarrow BaSO_{4}(s)downarrow +2HCl(aq)[/math]

This is an example of a so-called metathesis or partner-exchange reaction.

Copper is below hydrogen in the reactivity series of metals, so it is unable to displace hydrogen from sulphuric acid. It however reacts with conc. Sulphuric acid to liberate sulphur dioxide gas as per the equation —

Essentially, the salt that is produced depends on the acid, which is sulfuric acid (H2SO4). The two products which always occur in this type of reaction is water (H2O) and Carbon dioxide (CO2). The metallic carbonate loses the carbonate for anion in the acid, and water and CO2 is produced. My example is:

CaCO3 + H2SO4 → CaSO4 + H2O + CO2

The balanced equation is:

1 CaCO3 + 1 H2SO4 → 1 CaSO4 + 1 H2O + 1 CO2

Very simple.

We know that sulphur is [math]S[/math]. We also know that sulphuric acid is [math]H_2SO_4[/math].

So, theoretically, every atom of sulphur can be converted to a molecule of sulphuric acid. So, [math]1 mol S[/math] gives [math]1 mol H_2SO_4[/math].

[math]5000 g S imesdfrac{1}{32}frac{mol S}{g S}=156.25 mol S[/math].

So, we can theoretically get [math]156.25 mol H_2SO_4[/math], which is:

[math]156.25 mol H_2SO_4 imesdfrac{98}{1}frac{g H_2SO_4}{mol H_2SO_4}=15.3125 kg H_2SO_4[/math].

Note: You’ll probably never actually get a 100% yield. Also, the sulphuric acid produced won’t be 100% [math]H_2SO_4[/math], if you refer to the methods of producing it.

H(2)SO(4) + Zn -> ZnSO(4) + H(2)

Sulphuric acid + Zinc -> Zinc sulphate + Hydrogen gas

• Numbers in brackets are in subscript.