The reaction will happen in three steps: 1. The double bond will attack H+ to give a Markonikov product with formation of cation at second carbon atom. 2. There will be a hydride shift from the third carbon to the second one because tertiary carbo cations are more stable. 3. Chlorine will attack there thus forming 2-cholro-2-methylbutane
The reaction will happen in three steps: 1. The double bond will attack H+ to give a Markonikov product with formation of cation at second carbon atom. 2. There will be a hydride shift from the third carbon to the second one because tertiary carbo cations are more stable. 3. Chlorine will attack there thus forming 2-cholro-2-methylbutane
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First draw a picture of it
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First draw a picture of it
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The reaction will happen in three steps:
1. The double bond will attack H+ to give a Markonikov product with formation of cation at second carbon atom.
2. There will be a hydride shift from the third carbon to the second one because tertiary carbo cations are more stable.
3. Chlorine will attack there thus forming 2-cholro-2-methylbutane
The reaction will happen in three steps:
1. The double bond will attack H+ to give a Markonikov product with formation of cation at second carbon atom.
2. There will be a hydride shift from the third carbon to the second one because tertiary carbo cations are more stable.
3. Chlorine will attack there thus forming 2-cholro-2-methylbutane
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