17
Well, oxalic acid is a diacid that will react with two equiv sodium hydroxide to give sodium oxalate, and TWO equiv of water…
And so…
[math]HO(O=)CC(=O)OH(aq) + 2NaOH(aq) ightarrow ^{-}O(O=)C-C(=O)O^{-}Na_{2}^{+} + 2H_{2}O(l)[/math]
And is this balanced with respect to mass and charge?
More
VOTE
There is no reaction between the two, oxalic acid simply dissolves in water and becomes oxallic aid solution. If there is any equation, it would be:
C2H2O4 + H20 = C2O4- + 2H+ + H2O
2026-06-07
Well, oxalic acid is a diacid that will react with two equiv sodium hydroxide to give sodium oxalate, and TWO equiv of water…
And so…
[math]HO(O=)CC(=O)OH(aq) + 2NaOH(aq) ightarrow ^{-}O(O=)C-C(=O)O^{-}Na_{2}^{+} + 2H_{2}O(l)[/math]
And is this balanced with respect to mass and charge?
Well, oxalic acid is a diacid that will react with two equiv sodium hydroxide to give sodium oxalate, and TWO equiv of water…
And so…
[math]HO(O=)CC(=O)OH(aq) + 2NaOH(aq) ightarrow ^{-}O(O=)C-C(=O)O^{-}Na_{2}^{+} + 2H_{2}O(l)[/math]
And is this balanced with respect to mass and charge?
More
VOTE
There is no reaction between the two, oxalic acid simply dissolves in water and becomes oxallic aid solution. If there is any equation, it would be:
C2H2O4 + H20 = C2O4- + 2H+ + H2O
There is no reaction between the two, oxalic acid simply dissolves in water and becomes oxallic aid solution. If there is any equation, it would be:
C2H2O4 + H20 = C2O4- + 2H+ + H2O
More
VOTE