What is the balanced equation of copper II oxide with dilute sulfuric acid?

Try this:

CuO + H2SO4 → CuSO4 + H2O

for the more common copper (ii) oxide and

Cu2O + H2SO4 → Cu + CuSO4 + H2O

for cuprous oxide (copper (i) oxide)

You could start by writing the reaction equation:

CuO (s) + H2SO4(aq) → CuSO4(aq) + H2O(l)

This will give you the hydrated salt - which is usually CuSO4.5H2O

If you want to produce an anhydrous salt , you can take the dry CuSO4.5H2O - expose this to heat - usually in an oven with temperatures >> 105°C

The equation is

CuSO4.5H2O(s) →heat→ CuSO4(s) + 5H2O (g)

You cannot produce an anhydrous CuSO4 in this reaction in only one step.

Just a acid-base replacement reaction. The protons of sulfuric acid form water with the oxygen of copper oxide. Copper sulfate is the endproduct.

Copper oxide is a base. Therefore,the reaction between copper oxide and sulphuric acid is a neutralization reaction and the products are copper sulphate and water.

The reaction is as follows:

CuO + H2SO4 = CuSO4 + H2O

CuO + 2 H3O(+) + SO4(2-) → Cu(2+) + SO4(2-) + 3 H2O

You can drop the 2 ‘waters’ as well:

CuO + 2 H(+) + SO4(2-) → Cu(2+) + SO4(2-) + H2O

he wouldn’t get the white crystals because copper(II)oxide doesn’t react with dilute sulfuric acid.

It can only react with sulfuric acid and not dilute sulfuric acid.

Copper does not react with HCl acid, but copper oxide does react. A metal-acid reaction is always a redox reaction. Since copper has a higher reduction potential than hydrogen, it does not react with non-oxidising acids like HCl or dil.H2SO4.

But metal oxides are mostly basic substances and so they generally react with acids forming respective salts and water. Such acid-base type reactions (neutralisation) are non-redox in nature.

Copper oxide is a weak base, and it easily reacts with HCl forming soluble copper(II) chloride and water.

CuO(s) + 2HCl(aq) = CuCl2(aq) + H2O(l)

CuO + H2SO4 + H2O(l) = CuSO4 + 2H2O(l)

Change in Free Energy: ΔG(20C) = -79.9kJ (negative, so the reaction runs)

Change in Enthalpy: ΔH(20C) = -85.9kJ (negative, so the reaction is exothermic)

There’s some thermodynamics for you!

Copper oxide reacts with sulfuric acid to produce copper sulfate and water:

CuO + H2SO4 = CuSO4 + H2O

Change in Free Energy ΔG(20C) = -79.9kJ (negative, so the reaction runs)

Change in Enthalpy ΔH(20C) = -85.9kJ (negative, so the reaction is exothermic)

REACTION OF LEAD OXIDE WITH SULPHURIC ACID

SULPHURIC ACID (conc) is a good oxidising agent. It oxidises Pb(2+) to Pb(4+) and itself gets reduced to SO2.

Net Reaction is:

PbO + H 2SO 4 (conc) = H 2O + PbSO 4 +SO 2

Due to acidic SO2, pH of the solution decreases

HOPE IT WORKS