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First write the “molecular” equation
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Now write the ionic equation which shows anything that can dissociate , as ions .
Mg(s) + 2H+(aq) + 2Cl-(aq) → Mg2+ (aq) + 2Cl-(aq) + H2(g)
And finally write the net ionic equation . Delete anything that is common to both sides of the ionic equation . What remains is the net ionic equation
Mg(s) + 2H+ (aq) → Mg2+ (aq) + H2(g)
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2026-07-04
First write the “molecular” equation
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Now write the ionic equation which shows anything that can dissociate , as ions .
Mg(s) + 2H+(aq) + 2Cl-(aq) → Mg2+ (aq) + 2Cl-(aq) + H2(g)
And finally write the net ionic equation . Delete anything that is common to both sides of the ionic equation . What remains is the net ionic equation
Mg(s) + 2H+ (aq) → Mg2+ (aq) + H2(g)
First write the “molecular” equation
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Now write the ionic equation which shows anything that can dissociate , as ions .
Mg(s) + 2H+(aq) + 2Cl-(aq) → Mg2+ (aq) + 2Cl-(aq) + H2(g)
And finally write the net ionic equation . Delete anything that is common to both sides of the ionic equation . What remains is the net ionic equation
Mg(s) + 2H+ (aq) → Mg2+ (aq) + H2(g)
More
VOTE