What is the molarity of concentrated sulfuric acid if it is 96% by mass H2so4 and has a density of 1.84g/mL?

What you are asking about is the molarity of commercially available conc. H2SO4. Conc. Sulphuric acid is 18 Molar (or 36N) solution in water. In case you want to calculate by yourself : H2SO4 is 96% ie 960 ml in 1000ml of solution, total mass = 960ml x 1.84g/ml = 1766.4g

For Molarity: 1766.4/molecular wt. Of H2SO4

1766.4/98.08 which comes to around 18M. Hope this helps

We start with the 1.84 g/ml. We want moles/liter. We just convert units:

1.84 g /ml * 96/100 * 1 mole/ 98.01 g * 1000 ml/1 liter = 18.01 moles/l

The units all cancel out except the moles and liters. the 96/100 corrects for the fact that the concentrated acid is not quite pure.

Okay, quite easy. Use this simple formula and you'll get what you need.

There is a relationship between molarity, mass percent and density as follows:

m =%CDV

m = 0.96 x 1.84 x 1000 mL = 1 766.4 g

1 766.4 / 98 g/mol = 18.02 mol = 18.02 mol/L = 18.02 M

Oh thank god for simple math question :)))

1000g of solution contains 960g of H2SO4 which is 9.7859 moles. (Divide by Mr)

1000g of solution occupies 0.54347 dm^3 (mass divide by density)

Hence, molarity of solution is 9.7859mol divide by 0.54347dm^3

Which is equals to 18.0061M or 18.0M (3sf)

Hope this helps! :)

Molarity = Specific gravity X Purity X 1000/Equivalent weight X 100

=( 1.84*96*1000)/(98*100)=18.02 N

Density =1.84 g/ml

1000 ml solution weighs 1840 gm

96% by mass:

Conc= X*100/1840s

X= 96*1840÷100=1766.4 gm h2so4 presentin 1000ml solution

Molarity= 1766.4/98=18.02

M = n/V where n is the number of moles and V is the volume in litres,

d = density = 1.84 g/ml = 1840 g/L,

ie. weight of H2SO4 is 1840 g in 1 L of solution,

But H2SO4 is present 96% by weight in the solution i.e 0.96 x 1840 = 1766.4 g,

So M = n/V = 1766.4/98/1 where 98 is the molar mass of H2SO4,

Therefore M = 18.024 mol/L

well u got ur answer

just giving u a tip in my bad handwriting

Molecular weight of H2SO4 is 98.079 g-mol.

1 ml equals 1.84 g. Hence, 96 ml equals 96 x 1.84 = 176.64 g.

Therefore, 100 ml volume contains 176.64 g H2SO4. So 1 liter contains 1776.4 g.

Hence, the molarity is 1776.4/98.079 = 18.11 M.