What is the molecular equation of sodium oxalate + lead (II) nitrate?

Reaction between sodium oxalate and lead (II) nitrate is irreversible reaction:

Na2C2O4(aq) + Pb(NO3)2(aq) =2NaNO3(aq) + PbC2O4(s)

This is a double replacement reaction:

Na2C2O4 + Pb(NO3)2 =2NaNO3 + PbC2O4

ΔG(20C) = -56.0kJ (negative, so the reaction runs)

ΔH(20C) = -22.2kJ (negative, so the reaction is slightly exothermic)

So, now you’ve learned a little thermodynamics!