What is the oxidation number of N in AgNO3?

• Oxidation Number of AgNO3=[0]
• Oxidation number of Oxygen= -2
• Oxidation number of Ag= +1.
• So [+1] + [Ag]+ 3[-2]= 0
• So Oxidation Number of N= 6–1= +5.

oxidation no of Ag= +1

O =-2 but we have 3 Oxygen, therefore, 3X (-2)=-6

We have to find N, therefore, N= x

Lets do the simple calculation,

+1 + x -6= 0

x= 5

So, oxidation no of N in AgNO3 is +5 (Ans)