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Oxidation number of N in NaNO3 is +5.
O N of Na is +1 and that of O is -2. Suppose, O N of N is x.
So, +1 + x + 3*(-2) = 0
x = +5
Hope this helps.
More
VOTE
Without doing your homework, I will provide a hint.
Na is +1
O is -2
There are 3 oxygen.
Since this is a stable element the resultant charge is 0. So the + and - must balance.
2026-07-06
Oxidation number of N in NaNO3 is +5.
O N of Na is +1 and that of O is -2. Suppose, O N of N is x.
So, +1 + x + 3*(-2) = 0
x = +5
Hope this helps.
Oxidation number of N in NaNO3 is +5.
O N of Na is +1 and that of O is -2. Suppose, O N of N is x.
So, +1 + x + 3*(-2) = 0
x = +5
Hope this helps.
More
VOTE
Without doing your homework, I will provide a hint.
Na is +1
O is -2
There are 3 oxygen.
Since this is a stable element the resultant charge is 0. So the + and - must balance.
Without doing your homework, I will provide a hint.
Na is +1
O is -2
There are 3 oxygen.
Since this is a stable element the resultant charge is 0. So the + and - must balance.
More
VOTE