VOTE
NaOH → Na + OH
pOH = -log[OH]
= -log(2.5x10^-5)
pOH= 4.6.
pH = 14 — pOH
pH = 14 —4.6
pH = 9.4
More
2026-08-03
NaOH → Na + OH
pOH = -log[OH]
= -log(2.5x10^-5)
pOH= 4.6.
pH = 14 — pOH
pH = 14 —4.6
pH = 9.4
NaOH → Na + OH
pOH = -log[OH]
= -log(2.5x10^-5)
pOH= 4.6.
pH = 14 — pOH
pH = 14 —4.6
pH = 9.4
More
VOTE
NaOH → Na + OH
pOH = -log[OH]
= -log(2.5x10^-5)
pOH= 4.6.
pH = 14 — pOH
pH = 14 —4.6
pH = 9.4
NaOH → Na + OH
pOH = -log[OH]
= -log(2.5x10^-5)
pOH= 4.6.
pH = 14 — pOH
pH = 14 —4.6
pH = 9.4
More
VOTE