What is the product formed when propan-1-ol reacts with concentrated H2SO4?

This is temperature dependent reaction

If temp is below 413 K the product will be an ether

CH3CH2CH2-O- CH2CH2CH3

ie 1-propoxy propane

If temp is 443 K product will be an alkene

CH3CH= CH2 ie propene

Since, concentrated H2SO4 act as dehydrating agent, it will remove H2O from propan-1-ol

CH3CH2CH2OH +H2SO4 =>CH3CHCH2

Structure of CH3CHCH2 is CH3-CH=CH2