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Which one is most acidic 3-nitrobenzoic acid or 4-nitrobenzoic acid?
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Mike Webster
Which one is most acidic 3-nitrobenzoic acid or 4-nitrobenzoic acid?
-OH group shows +R and -I effect. When -OH group is at meta position, i.e in case of 3 Hydroxy benzoic acid, -OH group is not able to show +R effect and shows only -I effect.
In case of 4-Hydroxy benzoic acid, -OH group shows both, +R and -I (but +R>-I) therefore it donates electron.
Hence in the first case, it will act as electron withdrawing group hence will increase the acidic strength.
-OH group shows +R and -I effect. When -OH group is at meta position, i.e in case of 3 Hydroxy benzoic acid, -OH group is not able to show +R effect and shows only -I effect.
In case of 4-Hydroxy benzoic acid, -OH group shows both, +R and -I (but +R>-I) therefore it donates electron.
Hence in the first case, it will act as electron withdrawing group hence will increase the acidic strength.
Because iodo benzene acid is electron donating structure by resonance and it's electronegativity is also less than of chloro,bromo, and fluorobenzene acid. And we know that when electron donating group is attached to benzene ring then on ortho position electron get attached which is very stable.
Because iodo benzene acid is electron donating structure by resonance and it's electronegativity is also less than of chloro,bromo, and fluorobenzene acid. And we know that when electron donating group is attached to benzene ring then on ortho position electron get attached which is very stable.
-OH group shows +R and -I effect. When -OH group is at meta position, i.e in case of 3 Hydroxy benzoic acid, -OH group is not able to show +R effect and shows only -I effect.
In case of 4-Hydroxy benzoic acid, -OH group shows both, +R and -I (but +R>-I) therefore it donates electron.
Hence in the first case, it will act as electron withdrawing group hence will increase the acidic strength.
Hope that helped :)
-OH group shows +R and -I effect. When -OH group is at meta position, i.e in case of 3 Hydroxy benzoic acid, -OH group is not able to show +R effect and shows only -I effect.
In case of 4-Hydroxy benzoic acid, -OH group shows both, +R and -I (but +R>-I) therefore it donates electron.
Hence in the first case, it will act as electron withdrawing group hence will increase the acidic strength.
Hope that helped :)
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Because iodo benzene acid is electron donating structure by resonance and it's electronegativity is also less than of chloro,bromo, and fluorobenzene acid. And we know that when electron donating group is attached to benzene ring then on ortho position electron get attached which is very stable.
Because iodo benzene acid is electron donating structure by resonance and it's electronegativity is also less than of chloro,bromo, and fluorobenzene acid. And we know that when electron donating group is attached to benzene ring then on ortho position electron get attached which is very stable.
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