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Why do chloroform and benzene exhibit negative deviation from Raoult's law?
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Norman Sleep
Why do chloroform and benzene exhibit negative deviation from Raoult's law?
This is because when these liquids are mixed, H-bonding type interactions are formed between hydrogen atom of chloroform (partial positive charge due to 3 Cl atoms) and 'pi' electron cloud of benzene ring.
Thus, chloroform-benzene interactions are stronger than chloroform-chloroform and benzene-benzene interactions.
This is because when these liquids are mixed, H-bonding type interactions are formed between hydrogen atom of chloroform (partial positive charge due to 3 Cl atoms) and 'pi' electron cloud of benzene ring.Thus, chloroform-benzene interactions are stronger than chloroform-chloroform and benzene-benzene interactions.
This is because when these liquids are mixed, H-bonding type interactions are formed between hydrogen atom of chloroform (partial positive charge due to 3 Cl atoms) and 'pi' electron cloud of benzene ring. Thus, chloroform-benzene interactions are stronger than chloroform-chloroform and benzene-benzene interactions.
This is because when these liquids are mixed, H-bonding type interactions are formed between hydrogen atom of chloroform (partial positive charge due to 3 Cl atoms) and 'pi' electron cloud of benzene ring.Thus, chloroform-benzene interactions are stronger than chloroform-chloroform and benzene-benzene interactions.
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