Home >
Community >
Why is the peak-to-peak separation of cyclic voltammetry is 57 mV?
Upvote
23
Downvote
+ Chemistry
+ Electrochemistry
Posted by
Ogazi James
Why is the peak-to-peak separation of cyclic voltammetry is 57 mV?
The derivation of equation for cyclic voltammetry requires a lot of advanced calculus and differential equations based on the Fick's law of diffusion. This is not to discourage you but to show that the teacher is oversimplifying it. The derivation are provided in Allan J. Bard's Electroanalytical Chemistry. Why are they teaching cyclic voltammetry in sophomore classes?
The derivation of equation for cyclic voltammetry requires a lot of advanced calculus and differential equations based on the Fick's law of diffusion. This is not to discourage you but to show that the teacher is oversimplifying it. The derivation are provided in Allan J. Bard's Electroanalytical Chemistry. Why are they teaching cyclic voltammetry in sophomore classes?
Actually Im not a student at a usual university, so Im not a sophomore, but in an equivalent grade. Ive heard about the Ficks law of diffusion but I dont know the detail, so I want to study more and more, and to understand the derivation. Anyway, thank you for answering!More
The derivation of equation for cyclic voltammetry requires a lot of advanced calculus and differential equations based on the Fick's law of diffusion. This is not to discourage you but to show that the teacher is oversimplifying it. The derivation are provided in Allan J. Bard's Electroanalytical Chemistry. Why are they teaching cyclic voltammetry in sophomore classes?
The derivation of equation for cyclic voltammetry requires a lot of advanced calculus and differential equations based on the Fick's law of diffusion. This is not to discourage you but to show that the teacher is oversimplifying it. The derivation are provided in Allan J. Bard's Electroanalytical Chemistry. Why are they teaching cyclic voltammetry in sophomore classes?
More
VOTE
VOTE
VOTE