Home > Community > Why is the rate of solvolysis of t-butyl chloride lesser than that of 1-chloro-1-methylcyclohexane?
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Posted by
Larry Isaacs

Why is the rate of solvolysis of t-butyl chloride lesser than that of 1-chloro-1-methylcyclohexane?

Aryan Chopra  Follow

According to the definition given by The IUPAC Compendium of Chemical Terminology: The Gold Book[1], solvolysis is defined as:

Generally, reaction with a solvent, or with a lyonium ion or lyate ioninvolving the rupture of one or more bonds in the reacting solute.More specifically the term is used for substitution elimination andfragmentation reactions in which a solvent species is the nucleophile.

It clearly states that elimination occurring due to a solvent is also considered solvolysis and thus elimination in case of t-butyl is also considered.

This means you are right in your reasoning of t-butyl being the most susceptible to solvolysis among the given choices.

I believe this was an error from the question setter. They must have been referring to the substitution reaction due to the solvent but ended up creating a poorly worded question.


Reference:

(1) The IUPAC Compendium of Chemical Terminology: The Gold Book; Gold, V., Ed.; International Union of Pure and Applied Chemistry (IUPAC): Research Triangle Park, NC, 2019.

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