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Muazu Bala

Determine molecular weight of biomass based on ultimate analysis [duplicate]

Christopher Barrett  Follow

As a general rule, it is not a good idea to treat complex materials like wood as something you can calculate a mole of. You can of course analyze the material and get elemental rates, but that does not mean they are bonded in such way that this rate forms a minimum fraction which represents the whole thing.

When you calculate the number of moles of each atom in 100g, what you have is an estimation of the expected quantities in that sample. Undoubtedly, if you took different samples of the wood you would find different values, specially if sampling from different parts of the material.

As an exaggerated example, think about the elemental constitution of the human body, which is mainly 65% Oxygen, 18% Carbon, 10% Hydrogen and 3% Nitrogen in mass (source). With that in mind you can calculate a mole ratio of these elements and create a "representative formula". Obviously, though, there's no such thing as the human molecule, and you can't say that someone's body is X or Y moles of human.

Yet, like I originally answered, if you define what the representative formula is, you can calculate it's molar mass.

$$\ce {M}=4.0841*12.0107 + 5.77*1.00794+2.81*15.9994+0.0086*14.0067 = 99.947 \ \ce{g/mol}$$

Knowing ${\ce M}$, the number of moles is ${\ce 700,000/99.947 \approx 7004}$, and the concentration of biomass is $7004\ \ce{mol/m^3}$

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Jose Morales  Follow
No, the molar mass of a compound does not depend on how much of a sample you take. The formula for beech wood just gives the ratios of how many atoms are in a molecule, not their number in a sample.More
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Josh Velson  Follow
Does it matter what is assumed for the mass of the wood? For example, to get the formula for beech wood I assumed 100 grams. However, that formula would be different if I assumed a different mass such as 25 grams. In the end, the mole concentration would be different too.More
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Grace Vontobel  Follow
Please refer to my other question instead of this one, the new question will hopefully clarify what Im trying to do, More
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F Berschauer  Follow
I am not from this field, but I would suggest the density, humidity and fractional composition like in the question, that would probably specify the material sufficiently.More
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Jana Schwehm  Follow
Also, delete your answer so I can delete the question. Refer to the new question if you would like to comment. Sorry for the confusion.More
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