26
No, $\ce{FeCl3}$ is not formed upon reaction with Conc. $\ce{HCl}$. Both dilute and concentrated $\ce{HCl}$ give $\ce{FeCl2}$ as product.
$$\ce{Fe + 2HCl_{dil} -> Fe^2+ + 2Cl^- + H2 ^}$$ $$\ce{Fe + 2HCl_{conc} -> Fe^2+ + 2Cl^- + H2 ^}$$
Source: Vogel's Qualitative Inorganic Analysis
$$\ce{Fe + 2HCl_{dil} -> Fe^2+ + 2Cl^- + H2 ^}$$$$\ce{Fe + 2HCl_{conc} -> Fe^2+ + 2Cl^- + H2 ^}$$
More
-1
VOTE
2026-07-04
No, $\ce{FeCl3}$ is not formed upon reaction with Conc. $\ce{HCl}$. Both dilute and concentrated $\ce{HCl}$ give $\ce{FeCl2}$ as product.
$$\ce{Fe + 2HCl_{dil} -> Fe^2+ + 2Cl^- + H2 ^}$$ $$\ce{Fe + 2HCl_{conc} -> Fe^2+ + 2Cl^- + H2 ^}$$
Source: Vogel's Qualitative Inorganic Analysis
No, $\ce{FeCl3}$ is not formed upon reaction with Conc. $\ce{HCl}$. Both dilute and concentrated $\ce{HCl}$ give $\ce{FeCl2}$ as product.
$$\ce{Fe + 2HCl_{dil} -> Fe^2+ + 2Cl^- + H2 ^}$$$$\ce{Fe + 2HCl_{conc} -> Fe^2+ + 2Cl^- + H2 ^}$$
Source: Vogel's Qualitative Inorganic Analysis
More
-1
VOTE
VOTE
VOTE
VOTE
VOTE