How to find all 24 planes of $\{123\}$ family of planes?
For any of the $\left<111\right>$ directions, we have $3!$ i.e. $6$$\{123\}$ slip planes. And we have $4$$\left<111\right>$ slip directions for each plane. So in total $6\times 4 = 24$ slip systems.
How to find all 24 planes of $\{123\}$ family of planes?
For any of the $\left<111\right>$ directions, we have $3!$ i.e. $6$$\{123\}$ slip planes. And we have $4$$\left<111\right>$ slip directions for each plane. So in total $6\times 4 = 24$ slip systems.
For any of the $\left<111\right>$ directions, we have $3!$ i.e. $6$ $\{123\}$ slip planes. And we have $4$ $\left<111\right>$ slip directions for each plane. So in total $6\times 4 = 24$ slip systems.
For any of the $\left<111\right>$ directions, we have $3!$ i.e. $6$ $\{123\}$ slip planes. And we have $4$ $\left<111\right>$ slip directions for each plane. So in total $6\times 4 = 24$ slip systems.
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