Home >
Community >
SN1 vs SN2 in low concentration of nucleophile
Upvote
23
Downvote
+ Kinetics
Posted by
Lwanda Babalo Madlanga
SN1 vs SN2 in low concentration of nucleophile
Let us assume that the competing reaction is a Sn2 based pathway.
Sn2=k[substrate][nucleophile]
Sn1=k'[substrate]
Relative rate of products formed=(ie.. Sn1 to Sn2 product)=k'/(k[nucleophile]
Sn1 Reaction doesnot depend on concentration of the nucleophile , so more the concentration of nucleophile, the relative rate of Sn1 product diminishes.
Hence ,when the competing reaction is a Sn2 pathway, lesser concentration of nucleophile would favour the Sn1 pathway.
Let us assume that the competing reaction is a Sn2 based pathway.
Sn2=k[substrate][nucleophile]
Sn1=k'[substrate]
Relative rate of products formed=(ie.. Sn1 to Sn2 product)=k'/(k[nucleophile]
Sn1 Reaction doesnot depend on concentration of the nucleophile , so more the concentration of nucleophile, the relative rate of Sn1 product diminishes.
Hence ,when the competing reaction is a Sn2 pathway, lesser concentration of nucleophile would favour the Sn1 pathway.
Wow I never thought of it like that... You seem to be knowledgeable about organic chemistry. I am writing jee. Could you tell me how I should study organic chemistry and the books I should use?More
Let us assume that the competing reaction is a Sn2 based pathway.
Sn2=k[substrate][nucleophile]
Sn1=k'[substrate]
Relative rate of products formed=(ie.. Sn1 to Sn2 product)=k'/(k[nucleophile]
Sn1 Reaction doesnot depend on concentration of the nucleophile , so more the concentration of nucleophile, the relative rate of Sn1 product diminishes.
Hence ,when the competing reaction is a Sn2 pathway, lesser concentration of nucleophile would favour the Sn1 pathway.
Hope this helps.
Let us assume that the competing reaction is a Sn2 based pathway.
Sn2=k[substrate][nucleophile]
Sn1=k'[substrate]
Relative rate of products formed=(ie.. Sn1 to Sn2 product)=k'/(k[nucleophile]
Sn1 Reaction doesnot depend on concentration of the nucleophile , so more the concentration of nucleophile, the relative rate of Sn1 product diminishes.
Hence ,when the competing reaction is a Sn2 pathway, lesser concentration of nucleophile would favour the Sn1 pathway.
Hope this helps.
More
VOTE
VOTE