Home >
Community >
Why do 60S & 40S ribosomal subunits make an 80S ribosome (not 100S)?
Upvote
22
Downvote
+ Biochemistry
Posted by
Maggie Eades
Why do 60S & 40S ribosomal subunits make an 80S ribosome (not 100S)?
When a complex mixture of particles undergoes ultracentrifugation, they separate based on their shape and mass due to the force applied by the centrifuge and the counteracting frictional force of the solvent. You can read more about this procedure here. S stands for Svedberg, which is a measurement of the sedimentation rate of a particle. This is given by the formula $s=\frac{v}{a}$ where $s$ is the sedimentation coefficient and $v$ is the velocity a particle moves when an acceleration, $a$, is applied.
One svedberg is defined as exactly 10−13 s. Essentially the sedimentation coefficient serves to normalize the sedimentation rate of a particle by the acceleration applied to it. The resulting value is no longer dependent on the acceleration, but depends only on the properties of the particle and the medium in which it is suspended. Sedimentation coefficients quoted in literature usually pertain to sedimentation in water at 20°C.
A 1S particle, for example, would move at 10-13 m/s when an acceleration of 1 g is applied (ignoring diffusion).
What's important to realize is that the sedimentation rate of a particle depends not only on its mass but also on its shape (among other things) since its cross-sectional area determines the effective frictional force it experiences.
When a complex mixture of particles undergoes ultracentrifugation, they separate based on their shape and mass due to the force applied by the centrifuge and the counteracting frictional force of the solvent. You can read more about this procedure here. S stands for Svedberg, which is a measurement of the sedimentation rate of a particle. This is given by the formula $s=\frac{v}{a}$ where $s$ is the sedimentation coefficient and $v$ is the velocity a particle moves when an acceleration, $a$, is applied.
One svedberg is defined as exactly 10−13 s. Essentially the sedimentation coefficient serves to normalize the sedimentation rate of a particle by the acceleration applied to it. The resulting value is no longer dependent on the acceleration, but depends only on the properties of the particle and the medium in which it is suspended. Sedimentation coefficients quoted in literature usually pertain to sedimentation in water at 20°C.
A 1S particle, for example, would move at 10-13 m/s when an acceleration of 1 g is applied (ignoring diffusion).
What's important to realize is that the sedimentation rate of a particle depends not only on its mass but also on its shape (among other things) since its cross-sectional area determines the effective frictional force it experiences.
Svedberg unit means 10^-13 sec.... So that means 70s will take 70×10-13 seconds to settle down?More
Upvote
VOTE
Downvote
That's not a simple mathematical addition!
If those units were mass, for instance, you could (and should) add them: a 60g Lego piece combined with a 40g Lego piece will, of course, form a combo that has 100g.
a non-metric unit for sedimentation rate [...] The Svedberg coefficient is a nonlinear function. A particle's mass, density, and shape will determine its S value. (emphasis mine)
Funnily enough, most of my students thought that that S stands for Sedimentation. However, it's a tribute to Theodor Svedberg, winner of the Nobel Prize for Chemistry in 1926.
Thus, in a oversimplified explanation, the prokaryotic ribosome has two sub-units. The large sub-unit sediments at 50s, the small sub-unit sediments at 30s, but the two together (that is, the whole ribosome) sediments at 70s, not 80s.
The same way an eukaryotic ribosome has a large sub-unit that sediments at 60s, a small one that sediments at 40s, but the whole structure sediments at 80s, not 100s.
Also, the rRNAs that constitute the sub-units have their own sedimentation rates (in svedberg units) as well:
For a detailed explanation with all math you need, the other answers here and here explain it beautifully.
If those units were mass, for instance, you could (and should) add them: a 60g Lego piece combined with a 40g Lego piece will, of course, form a combo that has 100g.
a non-metric unit for sedimentation rate [...] The Svedberg coefficient is a nonlinear function. A particle's mass, density, and shape will determine its S value. (emphasis mine)
Funnily enough, most of my students thought that that S stands for Sedimentation. However, it's a tribute to Theodor Svedberg, winner of the Nobel Prize for Chemistry in 1926.
Thus, in a oversimplified explanation, the prokaryotic ribosome has two sub-units. The large sub-unit sediments at 50s, the small sub-unit sediments at 30s, but the two together (that is, the whole ribosome) sediments at 70s, not 80s.
The same way an eukaryotic ribosome has a large sub-unit that sediments at 60s, a small one that sediments at 40s, but the whole structure sediments at 80s, not 100s.
Also, the rRNAs that constitute the sub-units have their own sedimentation rates (in svedberg units) as well:
For a detailed explanation with all math you need, the other answers here and here explain it beautifully.
When a complex mixture of particles undergoes ultracentrifugation, they separate based on their shape and mass due to the force applied by the centrifuge and the counteracting frictional force of the solvent. You can read more about this procedure here. S stands for Svedberg, which is a measurement of the sedimentation rate of a particle. This is given by the formula $s=\frac{v}{a}$ where $s$ is the sedimentation coefficient and $v$ is the velocity a particle moves when an acceleration, $a$, is applied.
A 1S particle, for example, would move at 10-13 m/s when an acceleration of 1 g is applied (ignoring diffusion).
What's important to realize is that the sedimentation rate of a particle depends not only on its mass but also on its shape (among other things) since its cross-sectional area determines the effective frictional force it experiences.
When this was done with E. coli extracts, peaks were seen at 32S, 51S, 70S and 100S, depending on Mg2+ concentration. The researchers concluded that the 32S and 51S peaks were components of the 70S peak and that the 100S peak was a dimer of two 70S particles. They also determined that the mass of the 50S particle was about double the mass of the 30S particle which, together, added up to the mass of the 70S particle.
When a complex mixture of particles undergoes ultracentrifugation, they separate based on their shape and mass due to the force applied by the centrifuge and the counteracting frictional force of the solvent. You can read more about this procedure here. S stands for Svedberg, which is a measurement of the sedimentation rate of a particle. This is given by the formula $s=\frac{v}{a}$ where $s$ is the sedimentation coefficient and $v$ is the velocity a particle moves when an acceleration, $a$, is applied.
A 1S particle, for example, would move at 10-13 m/s when an acceleration of 1 g is applied (ignoring diffusion).
What's important to realize is that the sedimentation rate of a particle depends not only on its mass but also on its shape (among other things) since its cross-sectional area determines the effective frictional force it experiences.
When this was done with E. coli extracts, peaks were seen at 32S, 51S, 70S and 100S, depending on Mg2+ concentration. The researchers concluded that the 32S and 51S peaks were components of the 70S peak and that the 100S peak was a dimer of two 70S particles. They also determined that the mass of the 50S particle was about double the mass of the 30S particle which, together, added up to the mass of the 70S particle.
More
VOTE
VOTE
VOTE
That's not a simple mathematical addition!
If those units were mass, for instance, you could (and should) add them: a 60g Lego piece combined with a 40g Lego piece will, of course, form a combo that has 100g.
However, those numbers are Svedberg units, which is...
Funnily enough, most of my students thought that that S stands for Sedimentation. However, it's a tribute to Theodor Svedberg, winner of the Nobel Prize for Chemistry in 1926.
Thus, in a oversimplified explanation, the prokaryotic ribosome has two sub-units. The large sub-unit sediments at 50s, the small sub-unit sediments at 30s, but the two together (that is, the whole ribosome) sediments at 70s, not 80s.
The same way an eukaryotic ribosome has a large sub-unit that sediments at 60s, a small one that sediments at 40s, but the whole structure sediments at 80s, not 100s.
Also, the rRNAs that constitute the sub-units have their own sedimentation rates (in svedberg units) as well:
For a detailed explanation with all math you need, the other answers here and here explain it beautifully.
That's not a simple mathematical addition!
If those units were mass, for instance, you could (and should) add them: a 60g Lego piece combined with a 40g Lego piece will, of course, form a combo that has 100g.
However, those numbers are Svedberg units, which is...
Funnily enough, most of my students thought that that S stands for Sedimentation. However, it's a tribute to Theodor Svedberg, winner of the Nobel Prize for Chemistry in 1926.
Thus, in a oversimplified explanation, the prokaryotic ribosome has two sub-units. The large sub-unit sediments at 50s, the small sub-unit sediments at 30s, but the two together (that is, the whole ribosome) sediments at 70s, not 80s.
The same way an eukaryotic ribosome has a large sub-unit that sediments at 60s, a small one that sediments at 40s, but the whole structure sediments at 80s, not 100s.
Also, the rRNAs that constitute the sub-units have their own sedimentation rates (in svedberg units) as well:
For a detailed explanation with all math you need, the other answers here and here explain it beautifully.
More
VOTE