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Abrar Hafiz

Bromination of Phenylacetone

Craig Fairhurst  Follow

The mechanism that I have submitted in the edit of my post is correct. The reason both products are formed, is due to the the enol intermediate being planar with respect to the oxygen, allowing it to be attacked from either plane. This allows for the formation of a the so-called racemic mixture.

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Chee-Eng, Lim  Follow

The first step involves the formation of enol by protonation of the carbonyl oxygen. Then the electrophile adds to the enolate, and it may approach in either direction, from the top or the bottom of the plane of the enol.And so, a racemic mixture is obtained.

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Johnson Hanoch  Follow
I’m not sure why this answer is downvoted. From what I can tell, it’s correct.More
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